Particle A of mass mA=m2 moving along the x -axis with velocity v0 collides elastically with another particle B at rest having mass mB=m3 . If both particles move along the x axis after the collision, the change Δλ in de-Broglie wavelength of particle A , in terms of its de-Broglie wavelength λ0 before collision is:

Option 1 -

Δ λ = 3 2 λ 0

Option 2 -

Δ λ = 5 2 λ 0

Option 3 -

Δ λ = 2 λ 0

Option 4 -

Δ λ = 4 λ 0

0 5 Views | Posted 2 months ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    2 months ago
    Correct Option - 4


    Detailed Solution:

    Sol. V?1=2Ucm?-U1?2m/2Vom2+m3-Vo

    65Vo-VoV05

    λo=hcm2Voλf=hcM2Vo5

    Δλ=8hcmVo

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