The SI unit of a physical quantity is pascal-second. The dimensional formula of this quantity will be:

Option 1 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mrow> <mo>[</mo> <mrow> <mi>M</mi> <msup> <mrow> <mi>L</mi> </mrow> <mrow> <mo>−</mo> <mn>1</mn> </mrow> </msup> <msup> <mrow> <mi>T</mi> </mrow> <mrow> <mo>−</mo> <mn>1</mn> </mrow> </msup> </mrow> <mo>]</mo> </mrow> </mrow> </math> </span></p>
Option 2 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mrow> <mo>[</mo> <mrow> <mi>M</mi> <msup> <mrow> <mi>L</mi> </mrow> <mrow> <mo>−</mo> <mn>1</mn> </mrow> </msup> <msup> <mrow> <mi>T</mi> </mrow> <mrow> <mo>−</mo> <mn>2</mn> </mrow> </msup> </mrow> <mo>]</mo> </mrow> </mrow> </math> </span></p>
Option 3 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mrow> <mo>[</mo> <mrow> <mi>M</mi> <msup> <mrow> <mi>L</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msup> <msup> <mrow> <mi>T</mi> </mrow> <mrow> <mo>−</mo> <mn>1</mn> </mrow> </msup> </mrow> <mo>]</mo> </mrow> </mrow> </math> </span></p>
Option 4 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mrow> <mo>[</mo> <mrow> <msup> <mrow> <mi>M</mi> </mrow> <mrow> <mo>−</mo> <mn>1</mn> </mrow> </msup> <msup> <mrow> <mi>L</mi> </mrow> <mrow> <mn>3</mn> </mrow> </msup> <msup> <mrow> <mi>T</mi> </mrow> <mrow> <mn>0</mn> </mrow> </msup> </mrow> <mo>]</mo> </mrow> </mrow> </math> </span></p>
6 Views|Posted 6 months ago
Asked by Shiksha User
1 Answer
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6 months ago
Correct Option - 1
Detailed Solution:

S. I. unit Pascal – second   = N m 2 s e c  

= M L T 2 T L 2  

= M L 1 T 1  

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physics ncert exemplar solutions class 12th chapter two 2025

physics ncert exemplar solutions class 12th chapter two 2025

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