Physics Ncert Solutions Class 12th Physics NCERT Exemplar Solutions Class 12th Chapter Seven Class 12th Physics Alternating Current

Draw the effective equivalent circuit of the circuit shown in figure, at very high frequencies and find the effective impedance.

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Payal Gupta | Contributor-Level 10

8 months ago

This is a short answer type question as classified in NCERT Exemplar

Inductive reactance XL= 2 $π ϑ$ L

And capacitive reactance Xc= $\frac{1}{2 π ϑ C}$

For very high frequencies XL= infinity and Xc=0

When reactance of the circuit is infinite it will be considered as open circuit . when reactance of a circuit is zero it will be

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$I = Q_{0 . ω}$

$= \frac{C V}{\sqrt[]{L C}} = V \sqrt[]{\frac{C}{L}}$

$= 12 \sqrt[]{\frac{100 \times 1 0^{- 6}}{10 \times 1 0^{- 3}}}$

= 1.2 A

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Physics Ncert Solutions Class 12th 2023

Physics Ncert Solutions Class 12th 2023

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