Due to cold weather a 1m water pipe of cross-sectional area 1 cm2 is filled with ice at -10°C. Resistivity heating is used to melt the ice. Current of 0.5A is passed through 4 k Ω  resistance. Assuming that all the heat produced is used for melting, what is the minimum time required?

(Given latent heat of fusion for water/ice = 3.33 * 105 J kg-1, specific heat of ice = 2 * 103 J kg-1 and density of ice = 103 kg/m3)

Option 1 - <p>3.53 s</p>
Option 2 - <p>0.353 s</p>
Option 3 - <p>35.3 s</p>
Option 4 - <p>70.6 s</p>
6 Views|Posted 6 months ago
Asked by Shiksha User
1 Answer
A
6 months ago
Correct Option - 3
Detailed Solution:

Energy required to melt

Q = M S Δ T + M L  

1 0 1 * 2 * 1 0 3 * 1 0 + 1 0 1 * 3 . 3 3 * 1 0 5      

->3.53 * 104 J

Heat produce in wire

H = l2RT

  Q = 3 . 5 3 * 1 0 4 = ( 1 2 ) 2 * ( 4 * 1 0 3 ) * t

t = 3 . 5 3 * 1 0 4 * 4 4 * 1 0 3 = 3 5 . 3 s e c             

             

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In first condition R1 = 36 Ω  

In second condition R2 = 18  Ω

P 1 = V 2 R 1 = ( 2 4 0 ) 2 3 6               

P 2 = V 2 R 2 + V 2 R 2 = ( 2 4 0 ) 2 1 8 + ( 2 4 0 ) 2 1 8               

P 2 = ( 2 4 0 ) 2 9               

So   P 1 P 2 = ( 2 4 0 ) 2 / 3 6 ( 2 4 0 ) 2 / 9 = 1 4

x = 4

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Physics Current Electricity 2025

Physics Current Electricity 2025

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