For a given system find out
and
(forces exerted by the pulley on the support) respectively.
For a given system find out and (forces exerted by the pulley on the support) respectively.
Option 1 -
Option 2 -
Option 3 -
Option 4 -
-
1 Answer
-
Correct Option - 2
Detailed Solution:From F.B. Ds of
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= 0.92 * 1260 = 1161 m/s
For 2 kg block
T – 2g sin37 = 2a . (i)
For 4 kg block
4g – 2T =
2g – T = a . (ii)
T = (2g – a)
2g – a – 2g × = 2a
3a = 2g ×
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