For a uniform rectangular sheet shown in the figure, the ratio of moments of inertia about the axes perpendicular to the sheet and passing through O (the centre of mass) and O' (corner point) is:
For a uniform rectangular sheet shown in the figure, the ratio of moments of inertia about the axes perpendicular to the sheet and passing through O (the centre of mass) and O' (corner point) is:
Option 1 - <p>1/2</p>
Option 2 - <p>2/3<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 3 - <p>1/4<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 4 - <p>1/8<br><!--[endif]--></p>
4 Views|Posted 5 months ago
Asked by Shiksha User
1 Answer
V
Answered by
5 months ago
Correct Option - 3
Detailed Solution:
l? = 0.6M
l? = 0.8M
√l? ² + l? ² = 1
MI about 0 = M/12 (l? ² + l? ²)
I? = M/12
MI about O' = M/12 (l? ² + l? ²) + M (l? ²+l? ²)/4
I? = M/12 + M/4 = (4m)/12; I? /I? = 1/4
Similar Questions for you
= 3.15 kg m2
Distance of CM from 5 kg = 10*2/15 = 4/3m
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else.
On Shiksha, get access to
66K
Colleges
|
1.2K
Exams
|
6.9L
Reviews
|
1.8M
Answers
Learn more about...

Physics System of Particles and Rotational Motion 2025
View Exam DetailsMost viewed information
SummaryDidn't find the answer you were looking for?
Search from Shiksha's 1 lakh+ Topics
or
Ask Current Students, Alumni & our Experts
Have a question related to your career & education?
or
See what others like you are asking & answering





