For full scale deflection of total 50 divisions, 50 mV voltage is required in galvanometer. The resistance of galvanometer if its current sensitivity is 2 div/mA will be:

Option 1 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mn>2</mn> <mtext> </mtext> <mi>Ω</mi> </mrow> </math> </span></p>
Option 2 - <p>4 &lt;!-- [if gte mso 9]>&lt;xml&gt; <o:OLEObject Type="Embed" ProgID="Equation.DSMT4" ShapeID="_x0000_i1025" DrawAspect="Content" ObjectID="_1815902728"> </o:OLEObject> &lt;/xml&gt;&lt;![endif]--&gt;<span class="mathml" contenteditable="false"> <math> <mrow> <mi>Ω</mi> </mrow> </math> </span></p>
Option 3 - <p>1 &lt;!-- [if gte mso 9]>&lt;xml&gt; <o:OLEObject Type="Embed" ProgID="Equation.DSMT4" ShapeID="_x0000_i1025" DrawAspect="Content" ObjectID="_1815902737"> </o:OLEObject> &lt;/xml&gt;&lt;![endif]--&gt;<span class="mathml" contenteditable="false"> <math> <mrow> <mi>Ω</mi> </mrow> </math> </span></p>
Option 4 - <p>5<span class="mathml" contenteditable="false"> <math> <mrow> <mi>Ω</mi> </mrow> </math> </span>&nbsp;&lt;!-- [if gte mso 9]>&lt;xml&gt; <o:OLEObject Type="Embed" ProgID="Equation.DSMT4" ShapeID="_x0000_i1025" DrawAspect="Content" ObjectID="_1815902745"> </o:OLEObject> &lt;/xml&gt;&lt;![endif]--&gt;</p>
4 Views|Posted 6 months ago
Asked by Shiksha User
1 Answer
A
6 months ago
Correct Option - 1
Detailed Solution:

Current at full deflection,

l m a x = 5 0 2 = 2 5 m A             

R = V l m a x = 5 0 2 5 = 2 K Ω                

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Similar Questions for you

In first condition R1 = 36 Ω  

In second condition R2 = 18  Ω

P 1 = V 2 R 1 = ( 2 4 0 ) 2 3 6               

P 2 = V 2 R 2 + V 2 R 2 = ( 2 4 0 ) 2 1 8 + ( 2 4 0 ) 2 1 8               

P 2 = ( 2 4 0 ) 2 9               

So   P 1 P 2 = ( 2 4 0 ) 2 / 3 6 ( 2 4 0 ) 2 / 9 = 1 4

x = 4

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Physics Current Electricity 2025

Physics Current Electricity 2025

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