For the given circuit the current i through the battery when the key in closed and the steady state has been reached is__________.

 

Option 1 - <p>25 A</p>
Option 2 - <p>0 A</p>
Option 3 - <p>6 A</p>
Option 4 - <p>10 A</p>
8 Views|Posted 6 months ago
Asked by Shiksha User
1 Answer
A
6 months ago
Correct Option - 4
Detailed Solution:

In given circuit inductor behave as a simple wire so resultant circuit will be

Ref = 2 + 1 = 3 Ω  

V = IR


l = 3 0 3 = 1 0 A  

 

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Similar Questions for you

In first condition R1 = 36 Ω  

In second condition R2 = 18  Ω

P 1 = V 2 R 1 = ( 2 4 0 ) 2 3 6               

P 2 = V 2 R 2 + V 2 R 2 = ( 2 4 0 ) 2 1 8 + ( 2 4 0 ) 2 1 8               

P 2 = ( 2 4 0 ) 2 9               

So   P 1 P 2 = ( 2 4 0 ) 2 / 3 6 ( 2 4 0 ) 2 / 9 = 1 4

x = 4

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Physics Current Electricity 2025

Physics Current Electricity 2025

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