Four equal masses, m each are placed at the corners of a square of length l as shown in the figure. The moment of inertia of the system about an axis passing through A and parallel to DB would be :

 

Option 1 - <p><span lang="EN-IN">2m</span><span lang="EN-IN">l<sup>2</sup></span>&nbsp;</p>
Option 2 - <p><span lang="EN-IN">m</span><span lang="EN-IN">l<sup>2</sup></span></p>
Option 3 - <p><span lang="EN-IN">√3 ml<sup>2</sup></span>&nbsp;</p>
Option 4 - <p><span lang="EN-IN">3ml<sup>2</sup></span></p>
7 Views|Posted 5 months ago
Asked by Shiksha User
1 Answer
R
5 months ago
Correct Option - 4
Detailed Solution:

Kindly consider the following Image

 

Thumbs Up IconUpvote Thumbs Down Icon

Similar Questions for you

I = I 1 + I 2 + I 3

I 1 = m l 2 3

I 2 = m l 2 1 2 + 5 m l 2 4 = I 3

I = m l 2 3 + 2 [ m l 2 1 2 + 5 m l 2 4 ]

= m l 2 3 + 2 × 1 1 2 ( 1 6 ) m l 2

= ( 1 3 + 8 3 ) m l 2

= 9 3 m l 2 = 3 m l 2

According to question, we can write

l = 2 π r r = l 2 π

I 1 = m l 2 3 , a n d I 2 = m r 2 2 = m l 2 8 π 2

I 1 I 2 = m l 2 3 × 8 π 2 m l 2 = 8 π 2 3

Taking an Exam? Selecting a College?

Get authentic answers from experts, students and alumni that you won't find anywhere else.

On Shiksha, get access to

66K
Colleges
|
1.2K
Exams
|
6.9L
Reviews
|
1.8M
Answers

Learn more about...

Physics System of Particles and Rotational Motion 2025

Physics System of Particles and Rotational Motion 2025

View Exam Details

Most viewed information

Summary

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

or

Ask Current Students, Alumni & our Experts

Have a question related to your career & education?

or

See what others like you are asking & answering