Given figure shows few data points in a photo electric effect experiment for a certain metal. The minimum energy for ejection of electron from its surface is: (Plancks constant h = 6.62 × 10?³? J.s )
Given figure shows few data points in a photo electric effect experiment for a certain metal. The minimum energy for ejection of electron from its surface is: (Plancks constant h = 6.62 × 10?³? J.s )
Option 1 -
1.93eV
Option 2 -
2.10eV
Option 3 -
2.59eV
Option 4 -
2.27eV
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1 Answer
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Correct Option - 4
Detailed Solution:eVs = hv – φ
At Vs = 0 ⇒ hv = φ
⇒ φ = [6.62 × 10?³?][10¹?][5.5]
⇒ φ = ([6.62 × 10?³?][10¹?][5.5]eV) / [1.6 × 10?¹?]
= 2.27
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