If <math><mrow><mrow><mrow></mrow></mrow></mrow></math> <math> <mrow> <mi>a</mi> <mo>⋅</mo> <mi>b</mi> <mo>=</mo> <mrow> <mo>|</mo> <mrow> <mi>a</mi> <mo>×</mo> <mi>b</mi> </mrow> <mo>|</mo> </mrow> </mrow> </math> , then the <math> <mrow> <mi>θ</mi> </mrow> </math> angle <math><mrow></mrow></math> between a and b will be

a ⋅ b = | a × b | a b cos θ=ab sin θ a b _ a b _ = s i n θ c o s θ tan θ=1

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Scalars and Vectors Physics Motion in Plane Physics Class 11th

If $a \cdot b = | a \times b |$ , then the $θ$ angle between a and b will be

Option 1 -

60⁰

Option 2 -

45⁰

Option 3 -

75⁰

Option 4 -

90⁰

2 Views | Posted a week ago

Asked by Shiksha User

1 Answer

Answered by

Raj Pandey | Contributor-Level 9

a week ago

Correct Option - 2

Detailed Solution:

$a \cdot b = | a \times b | a b$ $cos θ = a b sin θ$

$\frac{\underline{a b}}{\underline{a b}} = \frac{s i n θ}{c o s θ}$

$tan θ = 1$

<math> <mrow> <mi>a</mi> <mo>⋅</mo> <mi>b</mi> <mo>=</mo> <mrow> <mo>|</mo> <mrow> <mi>a</mi> <mo>×</mo> <mi>b</mi> </mrow> <mo>|</mo> </mrow> <mi>a</mi> <mi>b</mi> </mrow> </math> <math> <mrow> cos <mi>θ</mi><mo>=</mo><mi>a</mi><mi>b</mi> sin <mi>θ</mi></mrow> </math> <math> <mrow> <mfrac> <mrow> <munder accentunder="true"> <mrow> <mi>a</mi> <mi>b</mi> </mrow> <mo stretchy="true">_</mo> </munder> </mrow> <mrow> <munder accentunder="true"> <mrow> <mi>a</mi> <mi>b</mi> </mrow> <mo stretchy="true">_</mo> </munder> </mrow> </mfrac> <mo>=</mo> <mfrac> <mrow> <mi>s</mi> <mi>i</mi> <mi>n</mi> <mi>θ</mi> </mrow> <mrow> <mi>c</mi> <mi>o</mi> <mi>s</mi> <mtext> </mtext> <mi>θ</mi> </mrow> </mfrac> </mrow> </math> <math> <mrow> tan <mi>θ</mi><mo>=</mo><mn>1</mn></mrow> </math>

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If $a \cdot b = | a \times b |$ , then the $θ$ angle between a and b will be

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If $a \cdot b = | a \times b |$ , then the $θ$ angle between a and b will be