In the Young's double slit experiment, the distance between the slits varies in time as d(t) = d? + a? sin(ωt); where d?, ω and a? are constants. The difference between the largest fringe width and the smallest fringe width obtained over time is given as :

Option 1 - (λD) / (d₀ + a₀)

Option 2 - (λD) / (d₀a₀)

Option 3 - (2λDa₀) / (d₀² - a₀²)

Option 4 - (2λD(d₀)) / (d₀² - a₀²)

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Answered by

Raj Pandey | Contributor-Level 9

5 months ago

Correct Option - 3

Detailed Solution:

β = λD / (d? + a? sinωt)
β? - β? = λD/ (d? - a? ) - λD/ (d? + a? )
= λD [ (d? + a? ) - (d? - a? ) / (d? ² - a? ²) ]
= 2λDa? / (d? ² - a? ²)

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Physics Ncert Solutions Class 12th 2023

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