In two cases, two identical conducting spheres are given equal charges, in one case of the same type whereas in another case of opposite type. The distance between the spheres is not large comparing with the diameter. Let F 1 and F 2  be the magnitude of the force of interaction between the spheres, as shown, then

 

Option 1 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <msub> <mrow> <mi>F</mi> </mrow> <mrow> <mn>1</mn> </mrow> </msub> <mo>&gt;</mo> <msub> <mrow> <mi>F</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msub> </mrow> </math> </span><br>&lt;!--[endif]--&gt;&lt;!-- [if gte mso 9]>&lt;xml&gt; <o:OLEObject Type="Embed" ProgID="Equation.DSMT4" ShapeID="_x0000_i1025" DrawAspect="Content" ObjectID="_1819717382"> </o:OLEObject> &lt;/xml&gt;&lt;![endif]--&gt;</p>
Option 2 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <msub> <mrow> <mi>F</mi> </mrow> <mrow> <mn>1</mn> </mrow> </msub> <mo>=</mo> <msub> <mrow> <mi>F</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msub> </mrow> </math> </span></p>
Option 3 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <msub> <mrow> <mi>F</mi> </mrow> <mrow> <mn>1</mn> </mrow> </msub> <mo>&lt;</mo> <msub> <mrow> <mi>F</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msub> </mrow> </math> </span></p>
Option 4 - <p>information is not sufficient to draw the conclusion</p>
2 Views|Posted 4 months ago
Asked by Shiksha User
1 Answer
R
4 months ago
Correct Option - 3
Detailed Solution:

In Case I when both are positively charged, due to induction positive charge moves outwards on spheres, increasing effective distance between centres of charge causing magnitude of the force to decrease.

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Physics Electric Charge and Field 2025

Physics Electric Charge and Field 2025

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