Two point charge Q each are placed at a distance d apart. A third point charge q is placed at a distance x from mid-point on the perpendicular bisector. The value of x at which charge q will experience the maximum Coulomb’s force is:

Option 1 -

x = d

Option 2 -

x = d 2

Option 3 -

x = d 2

Option 4 -

x = d 2 2

0 3 Views | Posted 3 weeks ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    3 weeks ago
    Correct Option - 4


    Detailed Solution:

    According to question, we can write

    F C A = F C B = K q Q x 2 + ( d 2 ) 2 F = 2 F C A c o s θ = 2 K q Q x [ x 2 + ( d 2 ) 2 ] 3 2                         

    For maxima of force  d F d x = 0 , s o  

    x = d 2 2

     

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