It is found that |A+B|=|A|. this necessarily implies.
(a) B=0
(b) A,B are antiparallel
(c) A,B are perpendicular
(d) A.B<0
It is found that |A+B|=|A|. this necessarily implies.
(a) B=0
(b) A,B are antiparallel
(c) A,B are perpendicular
(d) A.B<0
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1 Answer
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This is a Multiple Choice Questions as classified in NCERT Exemplar
Answer- a, b
Explanation - |A+B|= |A|or |A+B|2=|A|2
|A|2 +|B|2+2|A|B|cos = |A|2
|B| (|B|+2|A|cos )= 0
|B|=0 or |B|+2|A|cos =0
Cos =
If A and B are antiparallel then =180
-1=
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Please find the solution below:
after 10 kicks,
v? = 3tî v? = 24cos 60°î + 24sin 60°? = 12î + 12√3?
v? = v? – v? = (12 – 3t)î + 12√3?
It is minimum when 12 - 3t = 0 ⇒ t = 4sec
ω = θ² + 2θ
α = (ωdω)/dθ = (θ² + 2θ) (2θ + 2)
At θ = 1rad.
ω = 3rad/s and α = 12rad/s²
a? = αR = 12 m/s² a? = ω²R = 9 m/s² A? = √ (a? ² + a? ²) = 15 m/s²
a? = v? ²/4r
a_A? = (v? ²/r²) × r = v? ²/r
a_A = 3v? ²/4r
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