Measure of two quantities along with the precision of respective measuring instrument is
A = 2.5 m s–1 ± 0.5 m s-1
B = 0.10 s ± 0.01 s .
The value of A B will be
(a) (0.25 ± 0.08) m
(b) (0.25 ± 0.5) m
(c) (0.25 ± 0.05) m
(d) (0.25 ± 0.135) m
Measure of two quantities along with the precision of respective measuring instrument is
A = 2.5 m s–1 ± 0.5 m s-1
B = 0.10 s ± 0.01 s .
The value of A B will be
(a) (0.25 ± 0.08) m
(b) (0.25 ± 0.5) m
(c) (0.25 ± 0.05) m
(d) (0.25 ± 0.135) m
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1 Answer
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This is a multiple choice answer as classified in NCERT Exemplar
(a) As it is given that
A=2.5ms-1 0.5ms-1,
B= 0.10s 0.01s
X= AB= (2.5) (0.10)=0.25m
After rounding off two significant figures
AB= (0.25 )m
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Total moles of gas = n = nOxygen + nOxygen =
Volume of gas = 12 × 22.4 litre = 268.8 litre = 2.688 × 105 cm3
Viscosity = Pascal . Second
=
= x = 1, x + 2y = -1, -x + z = 1
y = -1, Z = 0
Viscosity = [P1A-1T0]
1 msD = 1mm
10 vsD = 9msD
1vsD = 0.9 MsD
L.C. = 1MSD – 1VSD = 1 – 0.9 = 0.1 mm
Zero error = 4LC = 0.4 mm
Reading = MSR + VSR + correction
= 4.1 cm + 6 * .01 cm + (-0.04 cm) = (4.1 + 0.06 – 0.04) cm
= 4.12 cm = 412 * 10-2 cm
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