ODBAC is fixed rectangular conductor of negligible resistance (CO is not connected) and OP is a conductor which rotates clockwise with an angular ve1locity omega Fig. The entire system is in a uniform magnetic field B whose direction in along the normal to the surface of the rectangular conductor ABDC. The conductor OP is in electric contact with ABDC. The rotating conductor has a resistance of  per unit length. Find the current in the rotating conductor, as it rotates by 180

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8 months ago

This is a long answer type question as classified in NCERT Exemplar

At t=o t=T/8= π / 4 w  the rod will make contact with side BD.at any time 0 π / 4 w

So magnetic flux through area ODQ is = B * a r e a O Q D = B * 1 2 Q D * O D

=B * 1 l t a n θ 2 * l

= 1 2 B L 2 w t a n θ = 1 2 B L 2 w s e c 2 w t

I=e/R

And R= λ x = λ l c o s w t  so I= 1 2 B L w c o s w t λ

Same result for other side too

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Physics Ncert Solutions Class 12th 2023

Physics Ncert Solutions Class 12th 2023

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