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Physics Physics NCERT Exemplar Solutions Class 11th Chapter Eleven Class 12th Centripetal and Centrifugal Force Laws of Motion Physics NCERT Exemplar Solutions Class 12th Chapter Five

One end of a massless spring of spring constant k and natural length $l_{0}$ is fixed while the other end is connected to a small object of mass m lying on a frictionless table. The spring remains horizontal on the table. If the object is made to rotate at an angular velocity $ω$ about an axis passing through fixed end, then the elongation of the spring will be

Option 1 -

$\frac{k - m ω^{2} l_{0}}{m ω^{2}}$

Option 2 -

$\frac{m ω^{2} l_{0}}{k + k ω^{2}}$

Option 3 -

$\frac{m ω^{0} l_{0}}{k - m ω^{2}}$

Option 4 -

$\frac{k + m ω^{2} l_{0}}{m ω^{2}}$

2 Views | Posted 2 months ago

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1 Answer

Answered by

Payal Gupta | Contributor-Level 10

2 months ago

Correct Option - 3

Detailed Solution:

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