Sand is being dropped from a stationary dropper at a rate of 0.5 kgs-1 on a conveyor belt moving with a velocity of 5ms-1. The power needed to keep the belt moving with the same velocity will be:
Sand is being dropped from a stationary dropper at a rate of 0.5 kgs-1 on a conveyor belt moving with a velocity of 5ms-1. The power needed to keep the belt moving with the same velocity will be:
Option 1 - <p>1.25 W</p>
Option 2 - <p>2.5 W</p>
Option 3 - <p>6.25 W</p>
Option 4 - <p>12.5 W</p>
2 Views|Posted 7 months ago
Asked by Shiksha User
1 Answer
A
Answered by
7 months ago
Correct Option - 4
Detailed Solution:
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= 0.92 * 1260 = 1161 m/s
For 2 kg block
T – 2g sin37 = 2a . (i)
For 4 kg block
4g – 2T =
2g – T = a . (ii)
T = (2g – a)
2g – a – 2g × = 2a
3a = 2g ×
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