Sometimes a radioactive nucleus decays into a nucleus which itself is radioactive. An example is
38sulphur
38Cl
38Ar(stable)
Assume that we start 1000 38S nuclei at time t=0. The number of 38Cl is of count zero at t=0 and will be again zero at t=
at what value of t, would the number of counts be a a maximum?
Sometimes a radioactive nucleus decays into a nucleus which itself is radioactive. An example is
38sulphur 38Cl 38Ar(stable)
Assume that we start 1000 38S nuclei at time t=0. The number of 38Cl is of count zero at t=0 and will be again zero at t= at what value of t, would the number of counts be a a maximum?
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1 Answer
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This is a Long Answer Type Questions as classified in NCERT Exemplar
Explanation- let 38S have N1 active nuclei and 38Cl have N2 active nuclei
+
N1=N0
+
Multiplying by and then integrating both sides we got
N2=
After solving it we get time t= (log )/
t= =
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