Sometimes a radioactive nucleus decays into a nucleus which itself is radioactive. An example is
38sulphur
38Cl
38Ar(stable)
Assume that we start 1000 38S nuclei at time t=0. The number of 38Cl is of count zero at t=0 and will be again zero at t=
at what value of t, would the number of counts be a a maximum?
Sometimes a radioactive nucleus decays into a nucleus which itself is radioactive. An example is
38sulphur 38Cl 38Ar(stable)
Assume that we start 1000 38S nuclei at time t=0. The number of 38Cl is of count zero at t=0 and will be again zero at t= at what value of t, would the number of counts be a a maximum?
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1 Answer
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This is a Long Answer Type Questions as classified in NCERT Exemplar
Explanation- let 38S have N1 active nuclei and 38Cl have N2 active nuclei
+
N1=N0
+
Multiplying by and then integrating both sides we got
N2=
After solving it we get time t= (log )/
t= =
Similar Questions for you
Q = [4 *4.0026 – 15.9994] *931.5 MeV
Q = 10.2 MeV
-(1)
for B,
for B,
-(2)
The reaction is X²? → Y¹²? + Z¹²?
Binding energies per nucleon are: X=7.6 MeV, Y=8.5 MeV, Z=8.5 MeV.
Gain in binding energy (Q) = (Binding energy of products) - (Binding energy of reactants)
Q = (120 × 8.5 + 120 × 8.5) - (240 × 7.6) MeV
Q = (2 × 120 × 8.5) - (240 × 7.6) MeV = 2040 - 1824 = 216 MeV.
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