Sometimes a radioactive nucleus decays into a nucleus which itself is radioactive. An example is

38sulphur h a l f l i f e 38Cl h a l f l i f e 38Ar(stable)

Assume that we start 1000 38S nuclei at time t=0. The number of 38Cl is of count zero at t=0 and will be again zero at t=  at what value of t, would the number of counts be a a maximum?

0 2 Views | Posted 4 months ago
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  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    4 months ago

    This is a Long Answer Type Questions as classified in NCERT Exemplar

    Explanation- let 38S have N1 active nuclei and 38Cl have N2 active nuclei

    d N 1 d t = - λ 1 N 1 + λ 1 N 1

    N1=N0 e - λ 1 t

    d N 2 d t = - λ 1 N 2 e ( - λ 1 t ) + λ 2 N 2

    Multiplying by eλ2tdt and then integrating both sides we got

    N2= Noλ1λ2-λ1(e-λ1t-e-λ2t)

    After solving it we get time t= (log λ1λ2 )/ λ1-λ2

    t= log2.480.622.48-0.62 = 2.303×2×0.30101.86=0.745s

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