The dimensions of angular impulse is equal to
The dimensions of angular impulse is equal to
Option 1 -
[M1L2T–1]
Option 2 -
[M1L2T1]
Option 3 -
[M1L2T2]
Option 4 -
[M1L1T–1]
-
1 Answer
-
Correct Option - 1
Detailed Solution:Angular impulse = Change in angular momentum
[J] = [mvr]
[J] = [M1L2T–1]
Similar Questions for you
By conservation of Angular momentum
Li = Lf

Position vector about O (r_o) = 5i + 5√3j
Force vector (F) = 4i - 3j
Torque about O (τ_o) = r_o × F
τ_o = (5i + 5√3j) × (4i - 3j)
τ_o = -15k - 20√3k = (-15 - 20√3)k
Position vector about Q (r_q) = -5i + 5√3j
Torque about Q (τ_q) = r_q × F
τ_q = (-5i + 5√3j) × (4i - 3j)
τ_q = 15k - 20√3k = (15 - 20√3)k
Kindly consider the following Image
r? = 10αt²î + 5β (t-5)?
v? = dr? /dt = 20αtî + 5β?
As L? = m (r? × v? )
So, at t=0, L=0
given L is same at t=t as at t=0
⇒ r? × v? = 0
⇒ (10αt²î + 5β (t-5)? ) × (20αtî + 5β? ) = 0
⇒ 50αβt² (î×? ) + 100αβt (t-5) (? ×î) = 0
⇒ 50αβt² k? - 100αβt (t-5) k? = 0
⇒ 50t² - 100t (t-5) = 0
⇒ 50t² - 100t² + 500t = 0
⇒ -50t² + 500t = 0
⇒ 50t (10 - t) = 0
⇒ t = 10 second
The direction of torque and angular momentum defines how and in which orientation an object will rotate or sustain its spin. This is important to understand in machines, athletic movements, and even natural phenomena, such as planetary motion.
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