A triangular plate is shown. A force F = 4i - 3j is applied at point P. The torque at point P with respect to point 'O' and 'Q' are :
A triangular plate is shown. A force F = 4i - 3j is applied at point P. The torque at point P with respect to point 'O' and 'Q' are :
Option 1 -
15 + 20√3, 15 – 20√3
Option 2 -
-15 - 20√3, 15 – 20√3
Option 3 -
-15 + 20√3, 15 + 20√3
Option 4 -
15 – 20√3, 15 + 20√3
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1 Answer
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Correct Option - 2
Detailed Solution:Position vector about O (r_o) = 5i + 5√3j
Force vector (F) = 4i - 3j
Torque about O (τ_o) = r_o × F
τ_o = (5i + 5√3j) × (4i - 3j)
τ_o = -15k - 20√3k = (-15 - 20√3)kPosition vector about Q (r_q) = -5i + 5√3j
Torque about Q (τ_q) = r_q × F
τ_q = (-5i + 5√3j) × (4i - 3j)
τ_q = 15k - 20√3k = (15 - 20√3)k
Similar Questions for you
Angular impulse = Change in angular momentum
[J] = [mvr]
[J] = [M1L2T–1]
By conservation of Angular momentum
Li = Lf

Kindly consider the following Image
r? = 10αt²î + 5β (t-5)?
v? = dr? /dt = 20αtî + 5β?
As L? = m (r? × v? )
So, at t=0, L=0
given L is same at t=t as at t=0
⇒ r? × v? = 0
⇒ (10αt²î + 5β (t-5)? ) × (20αtî + 5β? ) = 0
⇒ 50αβt² (î×? ) + 100αβt (t-5) (? ×î) = 0
⇒ 50αβt² k? - 100αβt (t-5) k? = 0
⇒ 50t² - 100t (t-5) = 0
⇒ 50t² - 100t² + 500t = 0
⇒ -50t² + 500t = 0
⇒ 50t (10 - t) = 0
⇒ t = 10 second
The direction of torque and angular momentum defines how and in which orientation an object will rotate or sustain its spin. This is important to understand in machines, athletic movements, and even natural phenomena, such as planetary motion.
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