The displacement current of 4.425 μ A is developed in the space between the plates of parallel plate capacitor when voltage is changing at a rate of 106 Vs-1. The area of each plate of the capacitor is 40 cm2. The distance between each plate of the capacitor is x × 10-3. The value of x is,

(Permittivity of free space, E 0 = 8 . 8 5 × 1 0 1 2 C 2 N 1 m 2 ) _ _ _ _ _ _ _ _ _ _  

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    Answered by

    Vishal Baghel | Contributor-Level 10

    a month ago

    According to definition of displacement current, we can write

    I d = ε 0 d ? d t = ε 0 d ( E S ) d t = ε 0 d ( V l S ) d t = ε 0 S l ( d V d t )

    l = 8 . 8 5 × 1 0 1 2 × 4 0 × 1 0 4 × 1 0 6 4 . 4 2 5 × 1 0 6 8 × 1 0 3 m

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