The displacement of a particle is given by x = (t – 2)2 where x is in metre and t in seconds. The distance covered by the particle in first 4 seconds is
(a) 4 m
(b) 8 m
(c) 12 m
(d) 16 m
The displacement of a particle is given by x = (t – 2)2 where x is in metre and t in seconds. The distance covered by the particle in first 4 seconds is
(a) 4 m
(b) 8 m
(c) 12 m
(d) 16 m
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1 Answer
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This is a multiple choice answer as classified in NCERT Exemplar
(b) x = (t-2)2
V= dx/dt= 2 (t-2)
And acceleration a = 2
When t =0 v= -4m/s
When t= 2s v= 0m/s
When t= 4s v= 4m/s
Distance travelled = area of graph =area of OAC+area of ABD= =8m
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Please find the solution below:
[h] = ML2T-1
[E] = ML2T-2
[V] = ML2T-2C-1
[P] = MLT-1
According to question, we can write
10 =
Average speed
(d) Initial velocity
Final velocity
Change in velocity
Momentum gain is along
Force experienced is along
Force experienced is in North-East direction.
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