The gravitational force between a H atom and a another particle of mass m will be given newton’s law
F=GMm/r2 where r in km
(a) M=mproton+melectron
(b) M=mproton+melectron-
(c) M is not relate to the mass of the hydrogen atom
(d) M=mproton+melectron-(|V|)= magnitude of the potential energy of electron in H atom.
The gravitational force between a H atom and a another particle of mass m will be given newton’s law
F=GMm/r2 where r in km
(a) M=mproton+melectron
(b) M=mproton+melectron-
(c) M is not relate to the mass of the hydrogen atom
(d) M=mproton+melectron-(|V|)= magnitude of the potential energy of electron in H atom.
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1 Answer
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This is a Multiple Choice Questions as classified in NCERT Exemplar
Answer- b
Explanation- F=GMm/r2
M=effective mass of hydrogen atom=mass of electron +mass of proton -B2/c
B.E of hydrogen atom = 13.6eV
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