The net external torque on a system of particles about an axis is zero. Which of the following are compatible with it ?
(a) The forces may be acting radially from a point on the axis.
(b) The forces may be acting on the axis of rotation.
(c) The forces may be acting parallel to the axis of rotation.
(d) The torque caused by some forces may be equal and opposite to that caused by other forces
The net external torque on a system of particles about an axis is zero. Which of the following are compatible with it ?
(a) The forces may be acting radially from a point on the axis.
(b) The forces may be acting on the axis of rotation.
(c) The forces may be acting parallel to the axis of rotation.
(d) The torque caused by some forces may be equal and opposite to that caused by other forces
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1 Answer
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This is a multiple choice type question as classified in NCERT Exemplar
a, b, c, d
As we know torque = r F = rFsin
a) when forces act radially angle =0 hence torque =0
b) when forces are acting on the axis of rotation r=0 torque=0
c) when forces acting parallel to the axis of rotation angle =0 so torque =0
d) when torque by forces are equal and opposite torque net = t1-t2=0
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Case – I : When disk slides down
Case – II : When disk rolls down
This is a multiple choice type question as classified in NCERT Exemplar
a, b, d
a) according to the perpendicular axes theorem statement 1 is wrong
b) As z’|z so distance between them = a
So according to parallel axes theorem Iz’=Iz+m (a/ )2= Iz+ma2/2
Hence b is true
c) z’ is not parallel to z hence Parallel axes does not applied so statement is false
d) as x and y axes are symmetrical . hence Ix=Iy so d is true
d) as x and y axes are symmetrical . hence Ix=Iy so d is true
This is a multiple choice type question as classified in NCERT Exemplar
b, c
a) When r>r’

Torque about z-axis t=r F
b) t’=r’ which is along negative z axis
c) tz=Fr = magnitude of torque about z axis where r is perpendicular between F and z axis so torque along positive z axis is greater than negative z axis.
d) We are always calculating resultant torque about common axis. Hence total torque not equal to combination of torque along both axis of z, because they are not on common axis.
This is a multiple choice type question as classified in NCERT Exemplar
(a), (b)As we know L= r p where r is position vector and p is the linear momentum . the direction of L is perpendicular to both r and p by right hand rule.
For particle 1
I1=r1 mv is out of the plane of the paper and perpendicular to r1 and p . similarly I2=r2 m (-v) is into the plane of the paper and perpendicular to r2 and -p.
Hence total angular momentum
L= L1+L2= I1=r1 mv+ (r2 m (-v)
L= mvd1-mvd2 as d2>d1
So total angular momentum will be inwards so I = l = mv (d2-d1)⊗
L= mvd1-mvd2 as d2>d1
So total angular momentum will be inwards so I = l = mv (d2-
This is a multiple choice type question as classified in NCERT Exemplar
(a), (c) For general rotational motion where axis of rotation is not symmetric . angular momentum L and angular velocity w need not be parallel. For general translational motion momentum p=mv hence p and v are always parallel.
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