Figure 7.5 shows a lamina in x-y plane. Two axes z and z′ pass perpendicular to its plane. A force F acts in the plane of lamina at point P as shown. Which of the following are true? (The point P is closer to z′-axis than the z-axis.)
(a) Torque τ caused by F about z axis is along ˆ -k.
(b) Torque τ′ caused by F about z′ axis is along ˆ -k.
(c) Torque τ caused by F about z axis is greater in magnitude than that about z axis.
This is a multiple choice type question as classified in NCERT Exemplar
b, c
a) When r>r’
Torque about z-axis t=rF
b) t’=r’which is along negative z axis
c) tz=Fr = magnitude of torque about z axis where r is perpendicular between F and z axis so torque along positive z axis is greater than negative z axis.
d) We are always calculating resultant torque about common axis. Hence total torque not equal to combination of torque along both axis of z, because they are not on common axis.
<p><span data-sheets-root="1">This is a multiple choice type question as classified in NCERT Exemplar</span></p><p>b, c</p><p><strong>a) </strong>When r>r’</p><div><div><picture><source srcset="https://images.shiksha.com/mediadata/images/articles/1745467795phpyD0YNm_480x360.jpeg" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/articles/1745467795phpyD0YNm.jpeg" alt="" width="189" height="141"></picture></div></div><p>Torque about z-axis t=r<span contenteditable="false"> <math> <mo>×</mo> </math> </span>F</p><p><strong>b)</strong> t’=r’<span contenteditable="false"> <math> <mo>×</mo> <mi>F</mi> </math> </span>which is along negative z axis</p><p><strong>c)</strong> t<sub>z</sub>=Fr = magnitude of torque about z axis where r is perpendicular between F and z axis so torque along positive z axis is greater than negative z axis.</p><p><strong>d) </strong>We are always calculating resultant torque about common axis. Hence total torque not equal to combination of torque along both axis of z, because they are not on common axis.</p>
This is a multiple choice type question as classified in NCERT Exemplar
(a), (b)As we know L= r p where r is position vector and p is the linear momentum . the direction of L is perpendicular to both r and p by right hand rule.
For particle 1
I1=r1mv is out of the plane of the paper and perpendicular to r1 and p . similarly I2=r2m (-v) is into the plane of the paper and perpendicular to r2 and -p.
Hence total angular momentum
L= L1+L2= I1=r1mv+ (r2m (-v)
L= mvd1-mvd2 as d2>d1
So total angular momentum will be inwards so I = l = mv (d2-d1)⊗
L= mvd1-mvd2 as d2>d1
So total angular momentum will be inwards so I = l = mv (d2-
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This is a multiple choice type question as classified in NCERT Exemplar
(a), (b)As we know L= r p where r is position vector and p is the linear momentum . the direction of L is perpendicular to both r and p by right hand rule.
For particle 1
I1=r1mv is out of the plane of the paper and perpendicular to r1 and p . similarly I2=r2m (-v) is into the plane of the paper and perpendicular to r2 and -p.
Hence total angular momentum
L= L1+L2= I1=r1mv+ (r2m (-v)
L= mvd1-mvd2 as d2>d1
So total angular momentum will be inwards so I = l = mv (d2-d1)⊗
L= mvd1-mvd2 as d2>d1
So total angular momentum will be inwards so I = l = mv (d2-d1)?
This is a multiple choice type question as classified in NCERT Exemplar
(a), (c) For general rotational motion where axis of rotation is not symmetric . angular momentum L and angular velocity w need not be parallel. For general translational motion momentum p=mv hence p and v are always parallel.
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