**The normal reaction 'N' for a vehicle of 800kg mass, negotiating a turn on a 30° banked road at maximum possible speed without skidding is_________* 10³ kg m/s².

[Given cos30° = 0.87, $μ_{5} = 0.2]$**

Option 1 - 6.96

Option 2 - 10.2

Option 3 - 12.4

Option 4 - 7.2

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Answered by

Alok Kumar Singh | Contributor-Level 10

6 months ago

Correct Option - 2

Detailed Solution:

In the frame of vehicle, vehicle is in equilibrium under the influence of pseudo force F_P

$F_{P} = \frac{m v^{2}}{R}$

N = mg cos 30° + F_P sin 30°

$\Rightarrow N = m g c o s 30 ° + \frac{m v^{2}}{R} s i n 30 ° . (i)$

, and

$f_{S} = \frac{m v^{2}}{R} c o s 30 ° - m g s i n 30 °$

By doing (1) * cos 30° - (2) * sin 30°, we have

$\Rightarrow N = \frac{800 * 10}{0.87 - 0.2 * 0.5} = \frac{800 * 10}{0.77} = 10.2 * 1 0^{3} k g m / s^{2}$

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The normal reaction 'N' for a vehicle of 800kg mass, negotiating a turn on a 30° banked road at maximum possible speed without skidding is_________* 103 kg m/s2. [Given cos30° = 0.87, μ 5 = 0 . 2 ]

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