The resultant of these forces $\vec{O P}, \vec{O Q}, \vec{Q R}, \vec{O S} a n d \vec{O T}$ is approximately. . . . . . .N

[Take $\sqrt[]{3} = 1.7, \sqrt[]{2} = 1.4 .$ Given $\hat{i} a n d \hat{j}$ unit vectors along x, y axis]

Option 1 -

$9.25 \hat{i} + 5 \hat{j}$

Option 2 -

$2.5 \hat{i} - 14.5 \hat{j}$

Option 3 -

$- 1.5 \hat{i} - 15.5 \hat{j}$

Option 4 -

$3 \hat{i} + 15 \hat{j}$

7 Views | Posted 2 months ago

Asked by Shiksha User

1 Answer

Answered by

Vishal Baghel | Contributor-Level 10

2 months ago

Correct Option - 1

Detailed Solution:

${\vec{F}}_{x} = [10 \times \frac{\sqrt[]{3}}{2} + 20 \times \frac{1}{2} + \frac{20}{\sqrt[]{2}} - \frac{15}{\sqrt[]{2}} - \frac{15 \sqrt[]{3}}{2}] = 9.25 \hat{i}$

${\vec{F}}_{y} = [15 \times \frac{1}{2} + 20 \times \frac{\sqrt[]{3}}{2} + 10 \times \frac{1}{2} - \frac{15}{\sqrt[]{2}} - \frac{20}{\sqrt[]{2}}] = 5 \hat{j}$

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The resultant of these forces $\vec{O P}, \vec{O Q}, \vec{Q R}, \vec{O S} a n d \vec{O T}$ is approximately. . . . . . .N

[Take $\sqrt[]{3} = 1.7, \sqrt[]{2} = 1.4 .$ Given $\hat{i} a n d \hat{j}$ unit vectors along x, y axis]

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The resultant of these forces O P → , O Q → , Q R → , O S → a n d O T → is approximately. . . . . . .N [Take 3 = 1 . 7 , 2 = 1 . 4 . Given i ^ a n d j ^ unit vectors along x, y axis]

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The resultant of these forces $\vec{O P}, \vec{O Q}, \vec{Q R}, \vec{O S} a n d \vec{O T}$ is approximately. . . . . . .N

[Take $\sqrt[]{3} = 1.7, \sqrt[]{2} = 1.4 .$ Given $\hat{i} a n d \hat{j}$ unit vectors along x, y axis]