The resultant of these forces is approximately. . . . . . .N
[Take Given unit vectors along x, y axis]
The resultant of these forces is approximately. . . . . . .N
[Take Given unit vectors along x, y axis]
Option 1 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mn>9</mn> <mo>.</mo> <mn>2</mn> <mn>5</mn> <mover accent="true"> <mi>i</mi> <mo>^</mo> </mover> <mo>+</mo> <mn>5</mn> <mover accent="true"> <mi>j</mi> <mo>^</mo> </mover> </mrow> </math> </span></p>
Option 2 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mn>2</mn> <mo>.</mo> <mn>5</mn> <mover accent="true"> <mi>i</mi> <mo>^</mo> </mover> <mo>−</mo> <mn>1</mn> <mn>4</mn> <mo>.</mo> <mn>5</mn> <mover accent="true"> <mi>j</mi> <mo>^</mo> </mover> </mrow> </math> </span></p>
Option 3 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mo>−</mo> <mn>1</mn> <mo>.</mo> <mn>5</mn> <mover accent="true"> <mi>i</mi> <mo>^</mo> </mover> <mo>−</mo> <mn>1</mn> <mn>5</mn> <mo>.</mo> <mn>5</mn> <mover accent="true"> <mi>j</mi> <mo>^</mo> </mover> </mrow> </math> </span></p>
Option 4 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mn>3</mn> <mover accent="true"> <mi>i</mi> <mo>^</mo> </mover> <mo>+</mo> <mn>1</mn> <mn>5</mn> <mover accent="true"> <mi>j</mi> <mo>^</mo> </mover> </mrow> </math> </span></p>
7 Views|Posted 6 months ago
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1 Answer
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Answered by
6 months ago
Correct Option - 1
Detailed Solution:
Similar Questions for you
= 0.92 * 1260 = 1161 m/s
For 2 kg block
T – 2g sin37 = 2a . (i)
For 4 kg block
4g – 2T =
2g – T = a . (ii)
T = (2g – a)
2g – a – 2g × = 2a
3a = 2g ×
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