The stopping potential for electrons emitted from a photosensitive surface illuminated by light of wavelength 491 nm is 0.710 V. When the incident wavelength is changed to a new value, the stopping potential is 1.43V. The new wavelength is

Option 1 - <p>382nm</p>
Option 2 - <p>309nm&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</p>
Option 3 - <p>329nm</p>
Option 4 - <p>400nm</p>
2 Views|Posted 5 months ago
Asked by Shiksha User
1 Answer
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5 months ago
Correct Option - 1
Detailed Solution:

Stopping potential defined in terms of wavelength as :

eV=hcλ? 0.710eV=hc491? 1.43eV=hcλ?

Using above two equation we can calculate :

λ=382nm

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