The value of current in the 6 Ω  resistance is:

Option 1 - <p>6A</p>
Option 2 - <p>10A</p>
Option 3 - <p>4A</p>
Option 4 - <p>8A</p>
3 Views|Posted 6 months ago
Asked by Shiksha User
1 Answer
A
6 months ago
Correct Option - 2
Detailed Solution:

Method-I : Using Kirchhoff's Law for loop B D A B B ,  we can write

1 4 0 + 2 0 l + 6 l 1 = 0 1 0 l + 3 l 1 = 7 0 . . . . . . . ( i )              

Using Kirchhoff's Law for loop A C B B A ,  

we can write

5 ( l l 1 ) + 9 0 6 l 1 = 0              

->-5l + 11l1 = 90 ........(ii)

Adding equation (1) with twice the equation (2), we have

2 5 l 1 = 2 5 0 l 1 = 2 5 0 2 5 = 1 0 A              

Method-II : Using concept of equivalent cell, we can w

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Similar Questions for you

In first condition R1 = 36 Ω  

In second condition R2 = 18  Ω

P 1 = V 2 R 1 = ( 2 4 0 ) 2 3 6               

P 2 = V 2 R 2 + V 2 R 2 = ( 2 4 0 ) 2 1 8 + ( 2 4 0 ) 2 1 8               

P 2 = ( 2 4 0 ) 2 9               

So   P 1 P 2 = ( 2 4 0 ) 2 / 3 6 ( 2 4 0 ) 2 / 9 = 1 4

x = 4

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Physics Current Electricity 2025

Physics Current Electricity 2025

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