The work functions of Caesium (Cs), Potassium (K) and Sodium (Na) are 2.14 e V , 2.30 e V and 2.75 e V respectively. If incident electromagnetic radiation has an incident energy of 2.20 e V , which of these photosensitive surfaces may emit photoelectrons?

Option 1 -

Na only

Option 2 -

Cs only

Option 3 -

Both Na and k

Option 4 -

K only

0 2 Views | Posted 3 weeks ago
Asked by Shiksha User

  • 1 Answer

  • R

    Answered by

    Raj Pandey | Contributor-Level 9

    3 weeks ago
    Correct Option - 2


    Detailed Solution:

    Incident energy = 2.20 e V

    If ? < 2.20 e V  electron will emit.

    ? > 2.20 e V No electron emission

    Only caesium will emit electron

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For no emission of electron

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According to Einstein’s photoelectric equation maximum kinetic energy of photoelectrons, K E  max  = E v φ

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e V s = h v - ?

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Relation between De-Broglie wavelength and K.E. is

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