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Physics System of Particles and Rotational Motion Physics Class 11th System of Particles and Rotational Motion

Three point particles of masses $10 k g, 1.5 k g$ and $2.5 k g$ are placed at there corners of a right angle triangle of sides $4.0 c m, 3.0; c m$ and $5.0 c m$ as shown in the figure. The centre of mass of the system is at a point:

Option 1 -

$0.6 c m$ right and $2.0 c m$ above $1 k g$ mass.

Option 2 -

$2.0 c m$ right and $0.9 c m$ above $1 k g$ mass.

Option 3 -

$1.5 c m$ right and $1.2 c m$ above $1 k g$ mass.

Option 4 -

$0.9 c m$ right and $2.0 c m$ above $1 k g$ mass.

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1 Answer

Answered by

Vishal Baghel | Contributor-Level 10

a month ago

Correct Option - 4

Detailed Solution:

Take $1 k g$ mass at origin

$X_{c m} = \frac{1 \times 0 + 1.5 \times 3 + 2.5 \times 0}{5} = 0.9 c m$

$Y_{c m} = \frac{1 \times 0 + 1.5 \times 0 + 2.5 \times 4}{5} = 2 c m$

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Three point particles of masses $10 k g, 1.5 k g$ and $2.5 k g$ are placed at there corners of a right angle triangle of sides $4.0 c m, 3.0; c m$ and $5.0 c m$ as shown in the figure. The centre of mass of the system is at a point:

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Three point particles of masses 10 k g , 1.5 k g and 2.5 k g are placed at there corners of a right angle triangle of sides 4.0 c m , 3.0 ; c m and 5.0 c m as shown in the figure. The centre of mass of the system is at a point:

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Three point particles of masses $10 k g, 1.5 k g$ and $2.5 k g$ are placed at there corners of a right angle triangle of sides $4.0 c m, 3.0; c m$ and $5.0 c m$ as shown in the figure. The centre of mass of the system is at a point: