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Two blocks of masses 10kg and 30kg are placed on the same straight line with coordinate (0, 0) cm and (x, 0) cm respectively. The block of 10kg is moved on the same line through a distance of 6cm towards the other block. The distance through which the block of 30kg must be moved to keep the position of centre of mass of the system unchanged is:

Option 1 -

4cm towards the 10kg block

Option 2 -

2cm away from the 10kg block

Option 3 -

2cm away from the 10kg block

Option 4 -

4cm away from the 10kg block

0 5 Views | Posted 2 months ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    2 months ago
    Correct Option - 3


    Detailed Solution:

    To keep,   Δ α c m = 0

         

          M 1 Δ x 1 + M 2 Δ X 2 = 0          

    ⇒ 1 0 × 6 + 3 0 Δ X 2 = 0      

    Δ X 2 = − 1 0 × 6 3 0

    Δ X 2 = − 2 c m        

    i.e. 2 cm towards the 10 kg block.

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