Two bodies A and B of same mass undergo completely inelastic one dimensional collision. The body A moves with velocity v 1 while body B is at rest before collision. The velocity of the system after collision is v 2 . The ratio v 1 : v 2  is

Option 1 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mn>1</mn> <mo>:</mo> <mn>2</mn> </mrow> </math> </span></p>
Option 2 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mn>2</mn> <mo>:</mo> <mn>1</mn> </mrow> </math> </span></p>
Option 3 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mn>4</mn> <mo>:</mo> <mn>1</mn> </mrow> </math> </span></p>
Option 4 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mn>1</mn> <mo>:</mo> <mn>4</mn> </mrow> </math> </span></p>
4 Views|Posted 6 months ago
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1 Answer
A
6 months ago
Correct Option - 2
Detailed Solution:

Sol. Before collision

It undergoes completely inelastic collision

Using conservation of linear momentum

Initial momentum = Final momentum

m v 1 = m v 2 + m v 2

m v 1 = 2 m v 2

v 1 v 2 = 2 1

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