Two bodies of masses m₁ = 5kg and m₂ = 3kg are connected by a light string going over a smooth light pulley on a smooth inclined plane as shown in the figure. The system is at rest. The force exerted by the inclined plane on the body of mass m₁ will be:

 [Take g = 10 ms^-2]

 

Correct Option - 2


Detailed Solution:

m₁ = 5kg                                                                      

m₂ = 3kg

As m₁ is in rest -

T = m_gg = 30

N = m₁ g cosq

T =    $m_{1}gsin\theta \Rightarrow 50sin\theta =30$

->sinθ  $=\raisebox{1ex}{$3$}\!\left/ \!\raisebox{-1ex}{$5$}\right.\Rightarrow \theta =37°$  

$\therefore N=50cos\theta =50cos37°=50\times \frac{4}{5}=40N$

 

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