Two bodies of unequal mass are moving in the same direction with equal kinetic energy. The two bodies are brought to rest by applying retarding force of same magnitude. How would the distance moved by them before coming to rest compare?

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8 months ago

This is a short answer type question as classified in NCERT Exemplar

According to work energy theorem = change in kinetic energy = work done

Kinetic energy of the body = force (displacement)

As kinetic energy is same so both will move with same velocities.

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This is a multiple choice answer as classified in NCERT Exemplar

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This is a multiple choice answer as classified in NCERT Exemplar

(c) m =150g =3/20kg

Time of contact =0.001s

U=126km/h= 126 × 1000 60 × 60 = 35 m s

V= -35m/s

Change in momentum of the ball = m (v-u)= 3 20 - 35 - 35 k g m / s

=21/2

F= dp/dt=- 21 / 2 0.001 N = - 1.05 × 10 4 N

Here – negative sign indicates that force will be opposite to the direction of movement of the ball be

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Physics NCERT Exemplar Solutions Class 11th Chapter Six 2025

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