Two buses P AN Q start form a point at the same time and move in a straight line and their positions are represented by Xp (t) = at + bt2 and XQ (t) = ft – t2. At what time, both the buses have same velocity?
Two buses P AN Q start form a point at the same time and move in a straight line and their positions are represented by Xp (t) = at + bt2 and XQ (t) = ft – t2. At what time, both the buses have same velocity?
Option 1 -
Option 2 -
Option 3 -
Option 4 -
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1 Answer
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Correct Option - 4
Detailed Solution:-(i)
-(ii)
(i) = (ii)
&
...more
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Please find the solution below:
[h] = ML2T-1
[E] = ML2T-2
[V] = ML2T-2C-1
[P] = MLT-1
According to question, we can write
10 =
Average speed
(d) Initial velocity
Final velocity
Change in velocity
Momentum gain is along
Force experienced is along
Force experienced is in North-East direction.
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