Two identical blocks A and B each of mass m resting on the smooth horizontal floor are connected by a light spring of natural L and spring constant K. A third block C of mass m moving with a speed v along the line joining A and B collides with A. The maximum compression in the spring is:
For an elastic collision where C comes to rest, and the compression in the spring is maximum, the velocities of A and B are equal (v). Using the conservation of mechanical energy: (1/2)mv? ² = 2 * (1/2)mv² + (1/2)kx² This gives the maximum compression x as: x = v? * √* (m / 2k)*
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