Two inclined planes are placed as shown in figure. A block in Projected from the Point A of inclined plane AB along its surface with a velocity just sufficient to carry it to the top Point B at a height 10m. After reaching the Point B the block slides down on inclined plane BC. Time it takes to reach to the point C from point A is t t ( 2 + 1 ) s . The value of t is__________.

(use g = 10 m/s2)

11 Views|Posted 6 months ago
Asked by Shiksha User
1 Answer
V
6 months ago

From conservation of Energy

1 2 m v 0 2 = m g h

v 0 = 1 0 2

For A to B

a = g s i n 4 5 ° = 1 0 2

T = t1 + t2

= 2 2 + 2 = 2 ( 2 + 1 )

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Physics Motion in Plane 2025

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