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Based on your academic credentials—969 marks in Class 12th, 94 marks in JEE Main with an All India Rank (AIR) of 83,592, and a group subject score of 596—you meet the eligibility criteria for admission to SASTRA University's B.Tech programs in Electrical and Electronics Engineering (EEE), Electronics and Communication Engineering (ECE), and Mechanical Engineering.

Admission Streams at SASTRA University:

1. Stream 1: Allocates 70% of seats based on a combined score of JEE Main marks and Class 12th scores.

2. Stream 2: Allocates 30% of seats based solely on Class 12th scores.

Your strong Class 12th performance positions you favorably in Stream 2.

Eligibility Criteria:

• Academic Requirements: A minimum of 60% aggregate in Class 12th with Mathematics and Physics as compulsory subjects, along with Chemistry/Biotechnology/Computer Science/Biology.

• Age Limit: Candidates should not be more than 20 years of age as of August 1, 2025.

Admission Process:

• Application: Complete the online application form available on SASTRA University's official website.

• Rank List: The university will release separate rank lists for Stream 1 and Stream 2 based on the respective criteria.

• Counseling: Admission offers will be made through a counseling process based on the rank lists.

Important Considerations:

• Cut-off Ranks: Specific cut-off ranks for EEE, ECE, and Mechanical Engineering are not publicly disclosed. Admission is competitive, and higher preference is often given to candidates with superior academic records.

Application Timeline: The application process typically begins in April, with rank lists and counseling sessions conducted in June.

Additionally, you may contact the admissions office directly:

• Phone: 04362-264101

Best wishes for your application process!