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Candidates can check below in detail:

• Each paper in the Mains exam is of three hours duration.
• Each paper carries 300 marks.
• Total marks: 600

Narayana Business School offers PGDM and MBA courses in full time mode through NBSAT. The entrance exam qualifying candidate can choose from the following courses:

• PGDM (Data Science & Analytics)
• PGDM (Quantitative Finance)
• PGDM (Dual Specialisation)
• MBA+PGPCE

This is a Long Answer Type Questions as classified in NCERT Exemplar

Explanation – speed of river V_r= 3m/s

Speed of swimmer V_s= 4m/s

(a) when swimmer starts swimming due north then its resultant velocity

V= $\sqrt[]{v_r^2+v_s^2}=\sqrt[]{3^2+4^2}=5m/s$

tan so ’N

(b) to reach at point B resultant velocity will be

V= $\sqrt[]{v_s^2-v_r^2}=\sqrt[]{4^2-3^2}=\sqrt[]{7}m/s$

tan $\theta =\frac{v_r}{v}=\frac{3}{\sqrt[]{7}}$

(c) time taken by swimmer t =d/v= d/4s

in case b time taken by swimmer to cross the river

t₁=d/v=d/ $\sqrt[]{7}$

so t1 

 

The table below presents the average package recorded during the Shikshapeeth College of Management and Technology placements in recent years:

Though I believe MFTech is a postgraduate degree programme capable enough to land you a decent job role in the Design industry, however, if really want to study further, in my opinion, getting an MBA degree or a PhD will benefit you a lot. 
An MBA degree in either Fashion Management or any relevant discipline related to your field of interest will open doors to leadership roles with higher salary prospects.

World University Rankings place California State University, Los Angeles at #1401+. Some others ranks of Cali State Uni, LA include #15 in Regional Universities West, #8 in Top Public Schools, #26 in Best Value Schools.

Another top-ranking publisher ranked California State University - Los Angeles at #1091 of 14,131 universities in the world, #280 of 2,496 universities in the U.S., #311 of 2,597 in North America, #28 of 249 in California, and #5 of 31 in Los Angeles. Also check California State University, Los Angeles Rankings 2025.

This is a Long Answer Type Questions as classified in NCERT Exemplar

Explanation – V_r= a? +b?

Velocity v_g= 5m/s

Velocity of rain w.r.t girl = V_r-V_g= a? +b? -5?

= (a-5)? +b?

a-5=0, a=5

case II 

v_g = 10m/s?

V_rg= V_r - V_g

 = a? +b? -10? = (a-10)? +b?

Rain appear to be fall at 45 degree so = b/a-10 =1

So b =-5

Velocity of rain = a? +b?

V_r = 5? -5?

Speed of rain V_r= $\sqrt[]{5^2+{(-5)}^2}=5\sqrt[]{2}m/s$

Yes, Nazareth College of Arts and Science generally offers direct admission to the BBA programme based on merit in the Class 12 examination. There is no entrance test requirement. However, candidates must meet the minimum eligibility criteria and complete the application process within the specified timeline. 

This is a Long Answer Type Questions as classified in NCERT Exemplar

Explanation- y=O, u_y= V_ocos $\theta$

a_y=-gcos $\theta$ , t =T

applying equation of kinematics

y=u_yt+ $\frac{1}{2}{a}_y$ t²

0 = V_ocos $\theta T$ +T^{2 $\frac{1}{2}(-gcos\theta )$}

T= $\frac{2V_{o}cos\theta }{gcos\theta }$

T= 2V₀/g

X= L, u_x=V_osin $\theta$  , a_x= gsin $\theta$  , t=T= $\frac{2V_o}{g}$

X=u_xt+ $\frac{1}{2}{a}_x{t}^2$

L= V_osin $\theta T+\frac{1}{2}gsin\theta T^2$

L= $\frac{4v_o^2}{g}$ sin $\theta$

No, you cannot study automotive engineering without having knowledge about concepts of Physics. This subject is fundamental part of Science that underpins many concepts in automotive engineering. Engine mechanics, vehicle dynamics, and materials Science are some key concepts in Physics. So, a strong understanding of physics is important for pursuing automotive engineering course.

Shikshapeeth College of Management and Technology has an impressive placement record. The placement statistics for 2025 are given in the table below:

Kindly go through the solution

Shikshapeeth College of Management and Technology has released some placement highlights for the 2025 placement drive. Refer to the table below to know more about the placements:

$\begin{array}{l}LetI={\displaystyle \int x^2{e^x}^{3}dx.}\\ let,t=x^3\Rightarrow dt=3x^{2}dx\cdot \Rightarrow \frac{dt}{3}=x^{2}dx\\ So,={\displaystyle \int \cdot }{e}^t\frac{dt}{3}=\frac{1}{3}{\displaystyle \int e^t}dt.\\ =\frac{1}{3}{e}^t+\; C\\ =\frac{e^{x^3}}{3}+C.\end{array}$

So, option (A) is correct.

BBA fee structure at Nazareth College of Arts and Science comprises tuition fees along with possible additional components such as refundable security deposits. Prospective students are encouraged to refer to the official college website or contact the admissions office for the most current and precise fee details. Since the fee structure is subject to revision, it's important to verify the information before proceeding with the application.

The number of students placed during Shikshapeeth College of Management and Technology placements has not been released yet. Once out it will be updated on this page. Check out the table below to know more about the placement statistics:

This is a Long Answer Type Questions as classified in NCERT Exemplar

Explanation – particle is projected from the point O.

Let time taken in reaching from point O to point P is T.

for journey O to P

y=0,u_y= V_osin $\beta$ ,a_y= -gcos $\alpha ,t=T$

y=u_yt + $\frac{1}{2}{a}_y{t}^2$

0= V_osin $\beta T+\frac{1}{2}\left(-gcos\alpha \right)T^2$

T[V_osin $\beta -\frac{gcos\alpha }{2}$ T]=0

T = time of flight = $\frac{2V_{o}sin\beta }{gcos\alpha }$

 

Motion along OX

x= L ,u_x= V_ocos $\beta$ , a_x= -gsin $\alpha$

t =T = $\frac{2V_{o}sin\beta }{gcos\alpha }$

x= u_xt+ $\frac{1}{2}{a}_x{t}^2$

L= V₀cos $\beta T$ + $\frac{1}{2}(-gsin\alpha )T^2$

L= T[V₀cos $\beta -\frac{1}{2}gsin\alpha T$ ]

L=  $\frac{2V_{o}sin\beta }{gcos\alpha }$ [V_ocos $\beta -\frac{V_{o}sin\alpha sin\beta }{cos\alpha }$ ]

L= $\frac{2v_o^{2}sin\beta }{g{cos}^2\alpha }\mathrm{c}\mathrm{o}\mathrm{s}?\left(\alpha +\beta \right)$

Z= sin $\beta \mathrm{c}\mathrm{o}\mathrm{s}?\left(\alpha +\beta \right)$

 = sin $\beta [cos\alpha cos\beta -sin\alpha sin\beta ]$

= $\frac{1}{2}(cos\alpha +sin2\beta -2sin\alpha .{sin}^2\beta )$

= ½ [sin2] $\beta cos\alpha -sin\alpha (1-cos2\beta )$

= $\frac{1}{2}[sin2\beta cos\alpha +cos2\beta .sin\alpha -sin\alpha ]$

= $\frac{1}{2}$  [sin(2 $\beta +\alpha$ )-sin $\alpha$ ]

For z maximum

2 $\beta +\alpha =\frac{\pi }{2}$  , $\beta =\frac{\pi }{4}-\frac{\alpha }{2}$

The placement package recorded at Shikshapeeth College of Management and Technology placements 2025 is given in the table below:

The UPSC IES 2026 Stage 2 is the Mains Exam. The examination comprises two papers. Both papers are based on the candidates' chosen engineering discipline. Details of subjects are provided below:

• Civil Engineering
• Mechanical Engineering
• Electrical Engineering
• Electronics and Telecommunication Engineering