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The Telangana (TS) BiPC (Biology, Physics, Chemistry) Intermediate 1st year syllabus includes English, Physics, Chemistry, Botany, and Zoology. The syllabus for each subject is based on the Telangana State Board of Intermediate Education (TSBIE) curriculum. 

(a) Smaller the size of the ion, more highly it is hydrated and hence greater is the mass of the hydrated ion and thus the ionic mobility become lesser. The extent of hydration decreases in the order.
Li⁺ < Na⁺ + < Rb+ < Cs+
Thus the mobility of Cs+ will be the highest

(b) Due to its smaller size lithium can form nitride directly as an exceptional behaviour unlike other alkali metals.

(c) It is because reduction potential depends upon sublimation energy, ionisation energy and hydration energy. Their resultant is almost constant for these ions.

The TNEA last round closing rank for BTech in Computer Science and Engineering at Mohamed Sathak A J College of Engineering in 2024 was 58,952 for the General category (All India).

The institute has a strong placement record since its inception. As of January 2025, the highest and average packages offered stood at INR 44.1 LPA and INR 6.99 LPA, respectively. The following table represents the CMRIT placement trends for the past three years:

(i) 2Na + 2H₂O → 2NaOH + H₂
(ii) 2Na + O₂ → Na₂O₂
(iii) Na₂O₂ + 2H20 → 2NaOH + H₂O₂

Sodium:

• Na⁺ions participate in the transmission of nerve signals, in regulating the flow of water across cell membranes.
• In the transport of sugars and amino acids into cell.

Potassium:

• K⁺ions activate many enzymes.
• Participate in the oxidation of glucose to produce ATP.

Magnesium:

• All enzymes that utilise ATP in phosphate transfer require magnesium as a cofactor.
• Mg is the central metal ion present in chlorophyll pigment in plants.

Calcium:

• Ca²⁺ ions are present in bones.
• plays important roles in neuromuscular function.

1.22

(a) Diameter of the sphere, d = 2.4 m, Radius, r = 1.2 m

Surface charge density,  = 80 μC/$m^2$  = 80$\times {10}^{-6}$  C/ $m^2$

Total charge on the surface of the sphere is given by Q =  A, where A = surface area of the sphere = 4 $\pi r^2$

Hence Q = 80 $\times {10}^{-6}\times 4\times \pi \times {1.2}^2$ C = 1.447 $\times {10}^{-3}$ C

(b) The total electric flux ( $<math><msub><mrow><mrow><mi>\phi </mi></mrow></mrow><mrow><mrow><mi>T</mi><mi>o</mi><mi>t</mi><mi>a</mi><mi>l</mi></mrow></mrow></msub></math>$ ) is given by ${\phi }_{Total}$ = $\frac{Q}{{?}_0},$

where ${?}_0$ = Permittivity of free space = 8.854$\times {10}^{-12}$$C^2{N}^{-1}$ $m^{-2}$,

Q = 1.447 $\times {10}^{-3}$ C

$<math><msub><mrow><mrow><mi>\phi </mi></mrow></mrow><mrow><mrow><mi>T</mi><mi>o</mi><mi>t</mi><mi>a</mi><mi>l</mi></mrow></mrow></msub></math>$ = 
 $\frac{1.447\mathrm{}\times {10}^{-3}}{8.854\mathrm{}\times {10}^{-12}}$ $C^{-1}N$ $m^2$= 1.63  $\times {10}^8$ $C^{-1}N$$m^2$

The institute has released its placement report for January 2025. According to the report released, the highest and average packages offered stood at INR 44.1 LPA and INR 6.99 LPA, respectively. The following table represents the CMRIT placement trends for the past three years:

It is due to high lattice energy of LiF as compared to LiCl.
LiCl is soluble in water because its hydration energy is higher than its lattice energy.

The institute has not released the CSE package details as of yet. Meanwhile, the CMRIT placement overall the highest package offered so far as of January 2025 stood at INR 44.1 LPA. In 2024, the highest package stood at INR 29 LPA. See the table below showcasing the CMRIT the highest package trends for a better understanding:

Li⁺ can polarize water molecules easily than the other alkali metal ions because of its small size.

1.21 Electric field intensity, E, at a distance d, from the centre of a sphere containing net charge q is given by the relation,

E =  $\frac{1}{4\pi {?}_0}$$\times \frac{q}{d^2}$

Where ${?}_0$= Permittivity of free space = 8.854 ×${10}^{-12}$ $C^2{N}^{-1}$$m^{-2},$

q= Net charge

E = 1.5 $\times {10}^3$ N/C

d = 2r = 20 cm = 0.2 m

q = E $4\pi {?}_0\times d^2$${}^{}$ = 1.5 $\times {10}^3\times 4\times \pi \times$ 8.854 $\times {10}^{-12}\times {0.2}^2$ C = 6.67 ×${10}^{-9}$C

= 6.67 nC

The net charge on the sphere is 6.67 nC

10.21 Consider that a single slit of width $d$ is divided in to $n$   smaller slits.

Therefore width of each slit,

$d^{\text{'}}=\frac{d}{n}$

Angle of diffraction is given by the relation,

$?=\frac{\frac{d}{d}}{d}?$ = $\frac{?}{d}$

Now, each of these infinitesimally small slit sends zero intensity in the direction of Ø.

Hence, the combination of these slits will give zero intensity.

The institute is known for its  placements and it is totally worth joining. As of January 2025, the highest and average packages offered stood at INR 44.1 LPA and INR 6.99 LPA, respectively. The following table represents the CMRIT placement trends for the past three years:

Since group 1 hydroxides and carbonates due to large size contain higher hydration energy than the lattice energy so, they are easily soluble in water. Whereas, in magnesium and calcium due to small size their lattice energy dominates over hydration energy they are sparingly soluble in water.

Yes, RB Skill Academy application forms are out now. Students seeking to enrol into the courses available at the institute need to visit the official website and start the process. Candidates can also connect with the institute's help desk to get more information and details regarding the admission process and chances of the institute. The form can be submitted once candidates provide the relevant details, including name, contact number, the latest educational qualification, etc.

10.20 Weak radar signals sent by a low flying aircraft can interfere with the TV signal received by the antenna. Hence, TV signal may get distorted, resulting in shaking of picture on the TV.

This is because superposition follows from the linear character of a differential equation that governs wave motion. If $y_1$ and $y_2$ are the solutions of the second order wave equation, then any linear combination of $y_1$ and $y_2$ will also be the solution of the wave equation.