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The syllabus of MPT Orthopaedics is considered moderate to difficult. It involves deep learning of musculoskeletal conditions, rehabilitation techniques, and patient management.
Students must understand complex therapies, anatomy, and clinical practices.
While it may feel tough at first, regular practice, clinical exposure, and proper guidance make the course manageable for dedicated students.

AIIMS Mangalagiri cutoff 2024 was released for admission to the MBBS course on the basis of NEET exam. The cutoff was released for different cateogories belonging to the All India quota. For the General AI category candidates, the cutoff rank was closed at 1930. Therefore, it is possible to get admission to the college with a rank of 1000, for the General AI category candidates. 

10.9 Wave length of the incident light, $?$ = 5000 $*{10}^{-10}$ m

Speed of light, c = 3 $*{10}^8$ m/s

Frequency of the incident light, $?$ =  $\frac{c}{?}$  =$\frac{3*{10}^8}{5000*{10}^{-10}}$ Hz= 6 $*{10}^{14}$ Hz

The wavelength and frequency of incident ray will be same as of reflected ray. So the wavelength of the reflected ray will be 5000 Å and the frequency will be 6 $*{10}^{14}$ Hz

When reflected ray is normal to the incident ray, the sum of incidence angle $?i$ and the reflected angle $?r$ will be 90 $°$

According to the law of reflection, the incidence angle and the reflected are same, i.e. $?i=?r$

Hence, $?i+?r$ = 2 $?i$ = 90 $°$

So$?i=?r=45°$

Therefore, the angle of incidence for the given condition is $45°$ .

1.17  (a) Net outward flux through the surface of the box , $\phi$ = 8.0 × ${10}^3$ ${\mathrm{Nm}}^2/$C

For a body containing net charge q, flux is given by the relation, 
 $\phi$ =$\frac{q}{{?}_0}$ 

where${?}_0$= Permittivity of free space = 8.854 
 $\times {10}^{-12}$ $C^2{N}^{-1}$$m^{-2}$

Hence q =  $\phi$ $\times {?}_0$= 8.0 ×${10}^3\times$ 8.854 $\times {10}^{-12}$ C = 7.0832 $\times {10}^{-8}$ C

= 7.0832 $\times {10}^{-2}\mu C$

(b) Net flux piercing out through a body depends on the net charge contained in the body. If net flux is zero, then it can be inferred that the net charge inside the body is zero. The body may have equal amount of positive and negative charges.

10.8 Refractive index of glass,  $?=1.5$

Let the Brewster angle be $?$

Brewster angle is related to $?$ by the equation

$\tan ??=?$

Or  = $?={\tan }^{-1}??$ =${\tan }^{-1}?1.5$ =56.31$°$

Hence, the Brewster angle for air to glass transition is 56.31 $°$

There are a number of factors through which candidates can compare the BBA course of ISHM Kolkata with other colleges and institutions.  First, candidates are advised to consider their concern; for instance, if fees are the concern, then candidates have to compare the colleges based on their fee structure and affordability. Similarly, candidates can compare the colleges and institutions based on different factors:

• Shiksha Rating
• Location
• Seats
• Cutoff
• Admission Criteria, etc.

10.7 Distance of the screen from the slits, D = 1 m

Wavelength of the light used,  ${?}_1$ = 600 nm

Angular width of the fringe in air,  ${?}_1$ = 0.2 $°$

Angular width of the fringe in water = ${?}_2$

Refractive index of water,  $?=\frac{4}{3}$

Refractive index is related to angular width as:

$?=\frac{{?}_1}{{?}_2}$ or

${?}_2=\frac{{?}_1}{?}$ = 0.2 $*\frac{3}{4}$ = 0.15 $°$

Hence, the angular width of the fringes in water will be 0.15 $°$

For admission to the BTech course at Alliance School of Computer Science and Engineering, students need to fulfil the minimum eligibility criteria in the first place. The selection criteria for this course is entrance-based i.e., JEE (Main)/JEE (Advanced)/Karnataka CET/COMED-K/AUEET (Alliance Undergraduate Engineering Entrance Test)/ or any other State-Level engineering entrance examination + PI. 

1.16 When the cube side is oriented so that its faces are parallel to the coordinate planes, number of field lines entering the cube is equal to the number of field lines piercing out of the cube. A as a result, net flux through the cube is zero.

Auburn University at Montgomery is among the top choices of international students. The university has a vast alumni network all over the world. The university graduates work in top companies such as State of Alabama, Alfa Insurance, Alabama Department of Public Health, Regions Bank, Army National Guard, and UAB Medicine. Auburn University at Montgomery has more than 32,000 alumni members worldwide. The university alumni network includes various famous personalities such as Robert T. Clark, LaTosha Brown, Ana Veselinovic, Steven L. Arnold, and more.

JECRC follows a two-year MBA programme at the PG level. Candidates are required to follow the admission process set by JECRC and admit the candidates on the basis of their perfromance in entrance exams such as CAT/MAT/XAT candidates are required to appear for these national level management exams in order to participate in the admission process.

As the amount of time needed to write an SOP might vary depending on the writer's writing abilities, experience, and research, there is no set time estimate for producing an SOP for MS in Mechanical Engineering. It may take several days or even weeks to write a well-crafted statement of purpose since it takes careful planning, research, and attention to detail.

To guarantee that the paper is well-written, proofread, and prepared for submission by the deadline, it is crucial to start writing as early as feasible. Getting input from instructors, mentors, or admissions specialists could increase the SOP's quality but take more time.

With a CUET-PG score of 105, your options for Masters in Political Science are limited, but some universities might still be accessible. While a score of 105 is considered low, some central universities and other institutions might offer admission based on their specific cutoffs, which can vary by category and program. You should check the websites of universities you are interested in to see if they have released their cutoffs and if your score is within range. 

1.15 (a) Electric field intensity, E = 3 $\times {10}^3$ î N/C

Magnitude of electric field intensity, $\left|E\right|$$=3\times {10}^3$ = 
 N/C

Side of the square, s = 10 cm = 0.1 m

Area of the square, A = $s^2$ = 0.01 $m^2$

The plane of the square is parallel to the y-z plane, hence the angle between the unit vector normal to the plane and electric field, $\theta$= 0 $°$

Flux ( $\phi )$ through the plane is given by the relation,  $\phi$ = $\left|E\right|A\cos ?\theta$ = $3\mathrm{}\times {10}^3\times 0.01\times \cos ?0°=30$
${\mathrm{Nm}}^2/$C

(b) When the normal to its plane make a 60 $°$ angle with x-axis,$\theta$  = 60 
 . From the equation $\phi$ =$\left|E\right|A\cos ?\theta$we get  = $\phi$ $3\mathrm{}\times {10}^3\times 0.01\times \cos ?60°=15$ ${\mathrm{Nm}}^2/$C

10.4 Distance between the slits, d = 0.28 mm = 0.28 $*{10}^{-3}$ m

Distance between the slits and the screen, D = 1.4 m

Distance between the central bright fringe and the fourth ( n = 4) fringe, u = 1.2 cm = 1.2 $*{10}^{-2}$ m

In case of a constructive interference, we have the relation for the distance between two fringes as : u = n $?\frac{D}{d},$ where n = order of fringes = 4 and $?$ = wavelength of the light used

Hence,  $?$ = $\frac{ud}{nD}$ = $\frac{1.2\mathrm{}*{10}^{-2}*0.28\mathrm{}*{10}^{-3}}{4*1.4}$ = 6 $*{10}^{-7}$ m = 600 $*{10}^{-9}$ m = 600 nm

Hence, wavelength of the light is 600 nm.

To get into Alliance School of Computer Science and Engineering for BTech course, candidates must meet the eligibility criteria set by the institute. Students must pass Class 12 with a minimum of 50% aggregate in Physics & Mathematics as compulsory subjects (5% relaxation for SC/ST).  Alliance School of Computer Science and Engineering offers full-time BTech courses of four years' duration. Students can get into this course based on entrance-exam.