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11 months agoContributor-Level 10
13.2 Atomic mass of neon isotope, = 19.99 u ad the abundance = 90.51 %
Atomic mass of neon isotope, = 20.99 u ad the abundance = 0.27 %
Atomic mass of neon isotope, = 21.99 u ad the abundance = 9.22 %
The average atomic mass of neon is given as:
m = = = = 20.1771 u
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11 months agoContributor-Level 10
- Physical appearance: All the alkali metals are silvery white, soft and light metals.
- Density: Because of the large size, these elements have low density which increases down the group except for potassium which is lighter than sodium (most likely due to an unexpected increase in the atomic size.).
- The melting and boiling points of the alkali metals are low indicating weak metallic bonding due to the presence of only a single valence electron in them.
- Atomic volume:The atomic volume, atomic and ionic radii rise as the group number reduces from Li to Cs.
- Melting and boiling points:The weak crystal lattice bonding causes low melting and boili
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11 months agoNew Question
11 months agoContributor-Level 8
Here are the steps to apply for Google scholarships:
- Research: Find open Google scholarships on their official site.
- Check Eligibility: Ensure you meet all requirements.
- Prepare Documents: Resume, transcripts, recommendation letters, essays.
- Apply Online: Fill form, upload documents.
- Submit: Review and submit before the deadline.
- Follow Up: Check email for updates.
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11 months ago
Contributor-Level 10
The minimum cutoff for a B.Tech in Computer Science and Engineering (CSE) at Indian Institutes of Technology (IITs) generally varies based on the specific IIT, the category of the candidate, and the year of admission. For top IITs like Bombay, Delhi, and Madras, the closing ranks for the General category can be below 200, while for other IITs, it may be in the range of 250 to 1000. For newer IITs, the closing ranks can range from 3000 to 6000.
The UPSC cut off marks is 75.41 for Prelims, and 741 for Mains. The final CSE cut off marks is 947 for the UPSC CSE 2024 based on the cumulative marks obtained by candidates in the Mains and
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11 months agoContributor-Level 10
No, candidates looking for course admission at Alliance School of Computer Science and Engineering cannot enrol for direct admissions. The institute admits students based on various national-level entrance exam scores, such as JEE Main/JEE Advance/KCET/CUET, etc., for various courses such as BTech, MCA, among others. It also considers the candidates' academic performance for final selection. The college also uses other parameters, such as scholastic and extracurricular records, for admission. The final selection of the candidate will be based on the overall performance in the Alliance admission selection process.
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11 months agoGuide-Level 15
Yes, Mohammad Ali Jauhar University offers Diploma courses through Mother Teresa Institute of Paramedical Sciences. The university offers Diploma in Optometry, Operation Theatre Technician, Physiotherapy and Nursing. Candidates must complete Class 12 in relevant subjects with at least 45% aggregate to apply for diploma.
Besides, the university also offers Diploma in various Engineering specialisations such as Civil, Computer Science, Electrical, Automobile, etc. Candidates can apply for Diplom in Engineering after completing Class 10 from a recognised board. Besides, the university also offers Diploma in Taxation/ Finance Accounti
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11 months agoBeginner-Level 3
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11 months agoContributor-Level 10
14.15 A acts as two inputs of the NOR gate and Y is the output. As shown in the following figure. Hence the output of the circuit is =

The truth table for the same is given as:
A | Y = ( ) |
0 | 1 |
1 | 0 |
This is the truth table of a NOT gate. Hence, this circuit functions as a NOT gate.
A and B are the inputs and Y is the output of the given circuit. By using the result obtained in solution (a), we can infer that the outputs of the first two NOR gates are and , as shown in the following figure

Above is given the inputs for the last NOR gate.
Hence, the output for the circuit can be written as:
Y = = = A.B
The truth table for the same can b
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11 months agoBeginner-Level 5
With 422 marks in the 12th grade and a cutoff score of 105, your chances of getting into a good college in Chennai are good, particularly for private engineering colleges or those with lower cutoffs.Here are some colleges in Chennai - SSN College of Engineering, Chennai Institute of Technology (CIT), Vel Tech Rangarajan Dr.Sagunthala R&D Institute of Science and Technology.
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11 months agoGuide-Level 15
Mohammad Ali Jauhar University offers more than 50 courses at UG, PG, diploma, certificate and doctoral levels. The university offers programmes in various streams such as Engineering, Management, Arts, Science, etc. Admission to most of the programmes offered at the university is merit-based. The university conducts an admission entrance test to select candidates for a few programmes such as BTech, MBA, B.Ed, BPharm, etc.
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11 months agoContributor-Level 10
The institute admits students based on various national-level entrance exam scores, such as JEE Main/JEE Advance/KCET/CUET, etc., for various courses such as BTech, MCA, among others. It also considers the candidates' academic performance for final selection. Students can check the table below to know detail course-wise selection criteria at Alliance School of Computer Science and Engineering:
| Courses | Selection Criteria |
|---|---|
| BTech | JEE (Main)/JEE (Advanced)/Karnataka CET/COMED-K/AUEET (Alliance Undergraduate Engineering Entrance Test)/ or any other State-Level engineering entrance examination + PI |
| MTech | Nationalised Management Test Scores and Alliance University M.Tech Computer Science and Engineering Entrance Test + Academic Performance, Oral Extempore Presentation and Personal Interview Performance |
| MCA | CUET score/Alliance University Master of Computer Application Entrance Test + Oral Extempore Presentation |
| PhD | Alliance Research Aptitude Test (ARAT) + Personal Interview + Evaluation of the research synopsis on a proposed dissertation work + Other parameters such as scholastic and extracurricular record, and work experience |
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11 months agoContributor-Level 10
14.14 A and B are the inputs of the given circuit. The output of the first NOR gate is + . It can be observed from the following figure that the inputs of the second NOR gate become the output of the first one.

Hence, the output of the combination is given as:
Y = = + = = = + =
The truth table for this operation is given as:
This is the truth table of an or gate. Hence, this circuit functions as an or gate.
A | B | Y ( = A + B) |
0 | 0 | 0 |
0 | 1 | 1 |
1 | 0 | 1 |
1 | 1 | 1 |
This is the truth table of an OR gate. Hence, this circuit functions as an OR gate.
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11 months agoContributor-Level 10
14.13 The output of the left NAND gate will be , as shown in the following figure:

Hence, the output of the combination of two NAND gates is given as:
Y = ( ).( ) = + = AB
Hence the circuit functions as an AND gate.
is the output of the upper left of the NAND gate and is the output of the lower half of the NAND gate, as shown in the following figure.

Hence, the output of the combination of the NAND gates will be given as:
Y = . = + = A + B
Hence, this circuit functions as an OR gate.
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11 months agoContributor-Level 9
The tables given below provide an overview of some popular Mass Communication and Media courses' syllabi for candidates' reference, and given below is the semester-wise curriculum of the Mass Communication and Media course:
MCM Syllabus Semester I | |
|---|---|
Writing for Media | Introduction to Communication |
Socio-Economic & Political Scenario | Introduction to Journalism (Reporting, Writing & Editing) |
MCM Syllabus Semester II | |
History of Print & Broadcasting in India | Media Laws & Ethics |
Print Journalism-I | |
MCM Syllabus Semester III | |
Development & Communication | Radio Journalism & Production |
Basics of Camera, Lights & Sound | Print Journalism-II |
MCM Syllabus Semester IV | |
Public Relations | Introduction to Advertising |
New Media | Public Relations Lab |
MCM Syllabus Semester V | |
Advertising Practices | Media Research |
Event Management: Principles & Methods | Environment Communication |
MCM Syllabus Semester VI | |
Media Organisation & Management | Contemporary Issues |
Global Media Scenario | Value Education |
Note: The information is sourced from external sites and may vary.
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11 months agoGuide-Level 15
Mohammad Ali Jauhar University offers admission to the BCA course based on merit of the aspirants in the last qualifying exam. Candidates must complete Class 12 with a minimum of 45% aggregate in any stream from any recognised board for admission to the course. Selected candidates have to report at the campus for document verification and fee payment to confirm their seat.
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11 months agoContributor-Level 10
14.12 A acts as the two inputs of the NAND gate and Y is the output, as shown in the following figure.

Hence, the output can be written as:
Y = = + = ……………(i)
The truth table for equation (i) can be drawn as:
A | Y = ( ) |
0 | 1 |
1 | 0 |
This circuit functions as a NOT gate. The symbol for this logic circuit is as shown below:

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11 months agoContributor-Level 10
ASCSE offers BTech, MCA, and M.Tech courses at the UG and PG levels. Apart from the UG and PG courses, the institute also offers PhD courses. The selection criteria are entrance-based. The institute admits students based on various national-level entrance exam scores, such as JEE Main/JEE Advance/KCET/CUET, etc., for various courses such as BTech, MCA, among others. It also considers the candidates' academic performance for final selection. The college also uses other parameters, such as scholastic and extracurricular records, for admission.
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11 months agoContributor-Level 10
Candidates wishing to pursue the MA course at CRSU can choose from the following specialisations:
- M.A. in History
- M.A. in Hindi
- M.A. in Psychology
- M.A. in Fine Arts
- M.A. in English
- M.A. in Economics
- M.A. in Political Science
Candidates can choose from the above mentioned and a plethora of other specialisations for the course.
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11 months agoContributor-Level 10
14.11 A and B are the inputs and Y is the output of the given circuit. The left half of the given figure acts as the NOR gate, while the right half acts as the NOT gate

Hence the output of the NOR gate is
This will be input for the NOT gate. Its output will be = A + B
So Y = A + B
Hence, this circuit functions as an OR gate.
A and B are the inputs and Y is the output of the given circuit. It can be observed from the following figure that the inputs of the right half NOR gate are the outputs of the two NOT gates.

Hence, the output of the given circuit can be written as:
Y = = = A + BHence this circuit functions as an AND gate.
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