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Yes,  PhD is available at Woxsen University. This programme is offered to students with a focus on research and academia. Moreover, this programme is offered in full-time and part-time modes. Candidates seeking admission can check the below table to know more about the programme:

Note: The above information is taken from official sources. However, it is subject to change.

According to the US News and World Report Rankings 2025, University of Hertfordshire has received a global rank of #1101.

Some of the other rankings at the university by the US News Rankings are given below -

1.11

(a) When polythene rubbed against wool, a number of electrons get transferred from wool to polythene. Hence, wool becomes positively charged and polythene negatively charged.

Amount of charge on the polythene piece, q = -3 $*{10}^{-7}$ C.

Amount of charge of 1 electron e = -1.6 $*10-19$

So number of electron transferred from wool to polythene

=
-$\frac{3\mathrm{}*{10}^{-7}}{-1.6\mathrm{}*{10}^{-19}}$1.875$*{10}^{12}$

(b) Since electron has a mass, so there will be transfer of mass also.

Mass of single electron,  $<math><msub><mrow><mrow><mi>m</mi></mrow></mrow><mrow><mrow><mi>e</mi></mrow></mrow></msub></math>$ = 9.1 $*{10}^{-31}$ kg

Total mass transferred from wool to polythene = 1.875 $*{10}^{12}*$9.1 $*{10}^{-31}$ kg

= 1.706 $*{10}^{-18}$kg$?$ negligible

Hence a negligible amount of mass is transferred from wool to polythene.

Candidates can get admission to the merit based admission process courses without appearing for any entrance exams. Candidates are required to apply for these courses through the application form that is available on the official website of the unievrsity. 

Some of the courses offering admission based on merit are:

• BA
• B.Ed
• UG Diploma
• BCom 
• BBA 

13.18 Half life of the fuel in the fission reactor, 
= 5 years = 5$*365*24*60*60s$

= 157.68 $*{10}^{6}s$

We know that in the fission of 1 g of ${}_{92}{}^{235}\mathit{U}$
 , the energy released = 200 MeV

1 mole i.e. 235 gm of ${}_{92}{}^{235}U$ contains 6.023 $*{10}^{23}$atoms

Therefore 1 gm of ${}_{92}{}^{235}\mathit{U}$
 contains =$\frac{6.023*{10}^{23}}{235}$= 2.563 $*{10}^{21}$ atoms

The total energy Q generated per gm of   ${}_{92}{}^{235}U$ = 200$*$2.563 $*{10}^{21}$ MeV/g = 5.126$*{10}^{23}$ 
 MeV/g = 5.126 $*{10}^{23}*1.6*{10}^{-19}*{10}^6$ J/g = 8.20$*{10}^{10}$ 
 J/g

Since the reactor operates only 80% of the time, hence the amount of ${}_{92}{}^{235}\mathit{U}$
 in 5 years is given by $\frac{0.8*157.68*{10}^6*1000*{10}^6}{8.20*{10}^{10}}$ = 1538 kg

Hence, initial amount of fuel = 2 $*1538kg$ = 3076 kg

The following are some of the best performing arts schools in the world:

• The Juilliard School (USA)
• Royal College of Music (UK)
• Conservatoire National Supérieur de Musique et de Danse de Paris (France)
• Guildhall School of Music & Drama (UK)
• Yale School of Drama (USA)

ASCSE offers BTech, MCA, and M.Tech courses at the UG and PG levels. Apart from the UG and PG courses, the institute also offers PhD courses. The selection criteria are entrance-based. The last date for all course applications is 15 May, 2025. Candidates who are looking for course admission can apply now at the official website.

13.17 The average energy released per fission of ${}_{94}{}^{239}Pu$  $E_{avg}$= 180 MeV

Amount of pure${}_{94}{}^{239}u$ , m = 1 kg = 1000 g

Avogadro's number,
$N_A$ = 6.023 $*{10}^{23}$

Mass number of ${}_{94}{}^{239}\mathit{P}\mathit{u}$  = 239 gm

Hence, number of atoms in 1000 g ${}_{94}{}^{239}Pu$, N =$\frac{6.023*{10}^{23}}{239}$ $*1000$= 2.52 $*{10}^{24}$

Total energy released during the fission of 1 kg of  ${}_{94}{}^{239}Pu$, E =$E_{avg}$ $*$N

= 180 $*$ 2.52$*{10}^{24}$ MeV = 4.536 $*{10}^{26}$ MeV

13.16 The fission can be shown as:

${}_{26}{}^{56}Fe\to 2{}_{13}{}^{28}Al$ 

It is given that atomic mass

m ( ${}_{26}{}^{56}Fe)$= 55.93494 u

m ( ${}_{13}{}^{28}Al)$= 27.98191 u

The Q-value of this reaction is given as:

Q = $\left[m\left({}_{26}{}^{56}Fe\right)-2m\left({}_{13}{}^{28}Al\right)\right]c^2$

= $\left[55.93494\mathrm{}-2\times 27.98191\right]c^2$

= -0.02888 $c^2$

= -0.02888$\times 931.5$  MeV

= - 26.902 MeV

The Q value of the fission is negative, therefore the fission is not possible energetically. Q value needs to be positive for a fission.

BTech full form is Bachelor of Technology,  a UG-level engineering degree course spanning 4 years, which is spread across 8 semesters. B Tech is a professional programme related to computers and technology that provides students with detailed knowledge about the core fundamentals of computer programming and software and hardware. Students can check the list of career options available after completing BTech from Alliance School of Computer Science and Engineering:

The university offers more than 50 full-time UG/ PG courses. CRSU admission process for the courses varies depending on the mode and course level. MDU offers courses in different streams such as Science, Law, Business & Management Studies, Teaching & Education, etc. The admission process for these courses can either be entrance or merit based. Candidates can learn more about the courses on offer through the official website of the university. 

Yes, students belonging to BC/OBC, MBC, and SC/ST categories can get admission with 40% marks in Class 12 with PCM subjects. For students from the OC category, a minimum of 45% is required. Students may apply through TNEA 2025 for admission, provided they meet the respective category-wise eligibility criteria.

13.11 Nuclear radius of the gold isotope,  ${}_{47}{}^{197}Au$ = $R_{Au}$

Nuclear radius of silver isotope,  ${}_{47}{}^{107}Ag$ = $R_{Ag}$

Mass number of gold,  $A_{Au}$ = 197

Mass number of silver,  $A_{Ag}$ = 107

The ratio of the radii of the two nuclei is related with their mass numbers as :

$\frac{R_{Au}}{R_{Ag}}$ = ${\left. [\frac{A_{Au}}{A_{Ag}}\right]}^{1/3}$ = ${\left. [\frac{197}{107}\right]}^{1/3}$ =1.2256

Hence, the ratio of the nuclear radii of the gold and silver isotope is 1.23

Yes, Mohamed Sathak A J College of Engineering offers several BTech specialisations. These include Computer Science and Engineering, Information Technology, Mechanical Engineering, Civil Engineering, Electrical and Electronics Engineering, and Electronics and Communication Engineering. Each programme is designed to provide students with practical knowledge and technical skills for a successful engineering career.

Alliance School of Computer Science and Engineering admissions for all courses are currently ongoing. Interested candidates can apply in online mode through the official website. The online application process is explained in the following steps:

Step 1: Visit the official website of Alliance School of Computer Science and Engineering (apply.alliance.edu.in/).

Step 2: Fill out the form.

Step 3: Complete the form and submit it.

The total tuition fee for the four-year BTech programme ranges from INR 1.5 Lacs to 2 Lakh. The fees may include other components apart from tuition. These figures are sourced from the official website and are subject to change. Students are advised to refer to the latest fee structure before applying.

After completing your BSc or MSc in Mass Communication, you have two major choices: either to opt for further education, which is a post-graduation or PhD, or you join an industry to gain work experience and earn money. It depends on your future goals and requirements, which way you would want to go.