Ask & Answer: India's Largest Education Community

The total tuition fees to pursue a PhD from Woxsen University range from INR 50,000 to INR 2.5 lakh. This fee is provided in a range, as the tuition fee for a few specialisations is greater than others. 

Note: The above-mentioned fee is as per the official sources. However, it is indicative and subject to change.

Ans.1.12

(a) Charge on sphere A, $q_A$ = 6.5 $*{10}^{-7}$ C

Charge on sphere B, $q_B$ = 6.5$*{10}^{-7}$ C

Distance between the spheres, r = 50 cm = 0.5 m

Force of repulsion between two spheres

F = $\frac{1}{4?{?}_0}$ $*\frac{q_1{q}_2}{r^2}$ , where ${?}_0$= Permittivity of free space = 8.854$*{10}^{-12}$ 
  $C^2{N}^{-1}$$m^{-2}$Therefore, F =  $\frac{1}{4*?*{8.854\mathrm{}*{10}^{-12}}_{}}$ $*\frac{6.5\mathrm{}*{10}^{-7}*6.5\mathrm{}*{10}^{-7}}{{0.5}^2}$N = 0.0152 N = 1.52  $*{10}^{-2}$N

(b) Charge on sphere A, $q_A$ = 2 $*$6.5  $*{10}^{-7}$C = 1.3

Charge on sphere B, $q_B$ = 2 $*$ 6.5 $*{10}^{-7}$C = 1.3

Distance between the spheres, r = $$ = 25 cm = 0.25 m

Force of repulsion between two spheres

F =  $\frac{1}{4?{?}_0}$ $*\frac{q_1{q}_2}{r^2}$, where ${?}_0$ = Permittivity of free space = 8.854  $*{10}^{-12}$ $C^2{N}^{-1}$$m^{-2}$Therefore, F = 
 $\frac{1}{4*?*{8.854\mathrm{}*{10}^{-12}}_{}}$ $*\frac{1.3\mathrm{}*{10}^{-6}*1.3\mathrm{}*{10}^{-6}}{{0.25}^2}$N = 0.243 N

Different concentrations of alkali metals in liquid ammonia gives different colours. The dilute solutions impart blue colour due to presence of ammoniated electrons whereas the concentrated solutions have copper bronze colour as  ammoniated metal ions are bound by free electrons.

AIIMS Mangalagiri cutoff 2024 was released for MSc admission on the basis of AIIMS Nursing. The cutoff was released as opening and closing cutoff ranks, for different categories belonging to the All India quota. Among the General AI category candidates, the last round closing ranks for MSc were between 217 and 265. 

Among the OBC AI category candidates, the ranks were closed between 255 and 356. 

The table given below provides the branch-wise cutoff for the General AI category candidates:

Yes, RB Skill Academy admissions are open. Interested students can visit the official website of the institute and start the process by registering themselves. Candidates need to eligibility and selection criteria to be eligible for admissions. So far no last date has been announced by the college, however, students are advised to apply as soon as possible to avoid any last minute rush. For more information, candidates can connect with the admission help desk of the college.

Potassium and caesium have much lower ionization enthalpy than that of lithium. As a result, these metals easily emit electrons on exposure to light. Due to this, K and Cs are used in photoelectric cells rather than lithium.

Alkali and alkaline earth metals are reducing agents. That is why these metals are not obtained by chemical reduction methods.

To apply for RB Skill Academy courses, students must first ensure that they meet the qualification of the desired course. Those who do can then proceed further. Students can visit the official website of the academy and fill out the admission form. At the time of filling out the form, students need to provide basic details, such as name, contact number, the latest educational qualification, etc. Once the form is duly filled-in, candidates can submit it and wait for further instructions.

13.23 Average atomic mass of magnesium, m = 24.312 u

Mass of magnesium isotope ${}_{12}{}^{24}\mathit{M}\mathit{g}$ ,= 23.98504u

Mass of magnesium isotope  ${}_{12}{}^{25}Mg$ ,$m_2$= 24.98584u

Mass of magnesium isotope  ${}_{12}{}^{26}Mg$ ,$m_3$= 25.98259u

Let the abundance of magnesium isotope  ${}_{12}{}^{24}Mg$ be ${\eta }_1$ = 78.99 %

Let the abundance of magnesium isotope  ${}_{12}{}^{25}Mg$ be ${\eta }_2$= x %

Therefore, the abundance of magnesium isotope  ${}_{12}{}^{26}Mg$ be ${\eta }_3$= (100 - 78.99 - x) %

= (21.01 – x)%

The average atomic mass can be expressed as:

m = $\frac{m_1{\eta }_1+m_2{\eta }_2+m_3{\eta }_3}{{\eta }_1+{\eta }_2+{\eta }_3}$ = $\frac{23.98504\times 78.99+24.98584x+25.98259(21.01-x)}{100}$ = $\frac{1894.578+24.98584x+545.894-25.98259x}{100}$=$\frac{2440.472-0.99675x}{100}$

24.312 = $\frac{2440.472-0.99675x}{100}$

x = 9.3%

Therefore the abundance of ${}_{12}{}^{25}Mg$ is 9.3% and the abundance of ${}_{12}{}^{26}Mg$ is (21.01 – 9.3)11.71%

The cheapest universities in london include:

1. University of East London (UEL): average fee = ~£15,560
2. London Metropolitan University: average fee = £13,000 - £18,000
3. University of West London: average fee = £11,000 - £15,000
4. University of Greenwich: average fee = £13,000 - £20,000

The number of intakes in seats in DSMNRU BA is decided based on certain factors. However, the university offers limited seats for its BA programme to ensure that only deserving and capable students are selected for this programme. The following are the major factors based on which Dr. Shakuntala Misra National Rehabilitation University's seat intake in BA is decided, which candidates can consider:

• Availability of Seats
• Number of students who applied
• Number of shortlisted students
• Academic record
• Performance in the entrance exam

13.21 We have the expression for nuclear radius as:

R = $R_0{A}^{1/3}$

Where $R_0$ = constant

A = mass number of nucleus

Let m be the average mass of the nucleus, hence mass of the nucleus = mA

Nuclear matter density $\rho$ can be written as

 $\rho =\frac{Massofthenucleus}{Volumeofthenucleus}$ = $\frac{mA}{\frac{4}{3}\pi R^3}$ = $\frac{3mA}{4\pi {\left(R_0{A}^{\frac{1}{3}}\right)}^3}$ = $\frac{3mA}{4\pi R_0^{3}A}$ = $\frac{3m}{4\pi R_0^3}$