Ask & Answer: India's Largest Education Community

Kindly consider the following Image 

dm = (m/L)dx
∴ T = (mω²/2L) (L² - x²)
∴ ΔL = ∫? (mω²/2Lπr²Y) (L² - x²)dx
= ΔL = mω²L²/3πr²Y

Yes, MSc course is available at JD School of Design (Powered by JD Institute), Bangalore. The institute offers MSc courses at the PG level. The candidate must meet the eligibility criteria to enrol for the MSc course admission set by the college. Aspirants must pass graduation. JD School of Design (Powered by JD Institute), Bangalore's admission process is merit-based.

Of course, you can. There are many colleges for a BA in German course offering admission based on the merit system. For example, University of Mumbai, Doon University, Dr. Bhimrao Ambedkar University, Ramdeobaba University, Modern College of Arts, Science and Commerce, Manipal Academy of Higher Education, etc.

Getting admission in College of Engineering & Management, Kolaghat without an entrance exam is generally not possible. Admissions to the courses offered are entrance-based and candidates must appear for the entrance exams accepted by the college. Interested candidates must contact the admission office of College of Engineering & Management, Kolaghat for more details on the same. 

See, the German course fee structure of every college varies depending on the course level and mode they offer. The fee structure also varies depending on the college type. For example, in government colleges, you'll find the German courses starting from INR 500 and going up to INR 55,000. On the other hand, the private colleges' fees start from INR 4,500 and go up to INR 9.04 Lakh.

Meanwhile, the course duration is fixed for degree courses, like 3 years for BA, 2 years for MA, and 3-6 years for a PhD. The course duration for certificates and diplomas can vary.

OH group is the more activating group and ortho-para director, hence ortho position attach will provide meta substituted product with respect to – CH₃ in option (C).

i = 60? , μ = √3
∴ 1 × sin (60? ) = √3 × sin r
=> r = 30?
∴ angle with x-axis = 60?

I believe German is quite challenging to learn, as German grammar has 3 genders, 4 cases, and different sentence structures present the biggest obstacles. You can obviously learn German, but it won't be inherently easy.

Depends on what you're good at. In my opinion, translating the other language from your native language is easier because when you understand the meaning of the sentence, it gets easier to speak. But in the case of German, it has a more complicated grammatical structure than English, so it will be a little difficult to translate English into German.

Yes, several BSc courses at Marwadi University are offered in honors mode. The standard BSc courses have a duration of 3 years however, honors mode of such BSc courses will have a duration of 4 years. Marwadi University BSc courses in honors mode share the same eligibility criteria and selection process. Candidates can learn more BSc honors courses at Marwadi University by visiting the official website.

That is because the German language comes from the Old High German word "Diutisc", which means "of the people". So, basically, Deutsch is the word Germans use for themselves and their language, as Germany is an outside term given by the Roman world.

M = φ? /I? = (B? A? )/I? = [ (μ? I? /2R? )πR? ²]/I?
[Diagram of two concentric coils]
M = (μ? πR? ²)/ (2R? )
M ∝ R? ²/R?

1/f_lens = (1.5/ (4/3) - 1) ( - 2/15) = f_lens = -60cm
∴ 1/fe = 2/ (-60) + 2/ (-15) => fe = -6 cm
∴ V = (14 × (-6)/ (14 + 6) = 4.2 cm from lens (virtual)

Velocity just before striking the ground
v? = √2gh
v? = √ (2×10×10) = 10√2 m/s
v? = -10√2?
If it reaches the same height, speed remains same after collision only the direction changes.
v? = 10√2 m/s
v? = 10√2?
|Impulse| = m|Δv|
= m|10√2? - (-10√2? )|
= 0.15 [2 (10√2)]
= 3√2 kg m/s
= 4.2 kg m/s

a = fr/m
∴ V = V? + at? = V? + (fr/m)t?
and α = 2Rfr/mR² = 2fr/mR
∴ ω = ω? - (2fr/mR)t?
∴ V = ωR ∴ v? + (fr/m)t? = ω? R - (2fr/m)t?
= (3fr/m)t? = V? = (fr/m)et?
∴ V = V? + V? /3 = 4V? /3
t? = mV? / (3μmg)
= V? /3μg

Yes, candidates can get admission in CEM- College of Engineering & Management, Kolaghat with 60% in Class 12. The minimum required aggregate for the same is 45% (40% in the case of reserved category). Candidates must appear for the JEE Main or WBJEE exam to take admission in the BTech course at CEM- College of Engineering & Management, Kolaghat. 

Yes, candidates who wish to apply for BSc courses at Marwadi University are required to appear for the CUET exam to qualify for BSc admissions at Marwadi University. The CUET entrance exam scores are used to determine whether a candidate receives admission or not at Marwadi University BSc courses. Candidates can register fo CUET through the official portal of NTA for CUET.

h = R / [ (2gR/V? ²) - 1] = R / [ (V²/K²V? ²) ] = KK² / (1 - K²)