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New Question

11 months ago

0 Follower 6 Views

A
alok kumar singh

Contributor-Level 10

11.39 

The preparation of ether by acid dehydration of primary alcohol involves the nucleophilic addition of alcohol molecule to the protonated alcohol molecule as shown below: -

However, under these conditions secondary and tertiary alcohols forms alkenes rather than ethers. The reason for this being that due to stearic hindrance, nucleophilic attack by the alcohol molecule on the protonated alcohol molecule does not take place. Instead protonated 20 and 30 alcohols lose a molecule of water to form stable carbocations. The stable carbocations so formed prefers to lose a proton to form alkenes instead of forming ethers by undergoing

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11 months ago

0 Follower 1 View

M
Mohit Sharma

Contributor-Level 10

PES University BA tuition fee is INR 3.6 lakh. Additionally, the one-time fee is INR 10,000 and hostel charges are INR 1.81 lakh. Students have to pay the first semester fee or the prescribed admission fee amount for the admission confirmation. The mentioned fee is sourced from the official website/ sanctioning body. It is still subject to changes and hence, is indicative.

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11 months ago

0 Follower 32 Views

C
Chanchal Jain

Contributor-Level 8

RRB NTPC percentile based normalisation is done to check the performance of candidates in each exam shift. The raw score is converted to the percentile score in the range between 100 to 0.

 

New Question

11 months ago

0 Follower 13 Views

A
alok kumar singh

Contributor-Level 10

11.38 

According to the question we have to perform the following conversion: -

The above conversion can be done easily by dehydrating 1- propanol with conc.H2SO4 at 413 K.

The mechanism of the above reaction is as follows : -

The mechanism is given below: -

In the first step, the alcohol gets protonated by the acid present to give a protonated alcohol.

In the second step, the nucleophilic attack of another alcohol molecule on the protonated alcohol gives us 1-propoxypropane as the desired product.

New Question

11 months ago

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A
alok kumar singh

Contributor-Level 10

11.37

Williamson synthesis is basically a SN2 reaction of a primary alkyl halide with an alkoxide ion. The basic mechanism for this reaction is

Now consider this reaction,

This reaction proceeds as conventional Williamson synthesis. But if secondary or tertiary alkyl halides are taken in place of primary alkyl halides, then elimination would compete over substitution reaction, which will result in the formation of alkenes. The reason is alkoxides are better nucleophiles as well as strong bases. Therefore, they react with alkyl halides resulting in an elimination reaction.

New Question

11 months ago

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H
Himanshu Singh

Contributor-Level 10

To secure a seat in the BPharm programme at MVN University, applicants must meet the required cutoff, perform well in the entrance exam, and participate in the HSTES counselling process. Completing all necessary steps in the admission process is essential.

New Question

11 months ago

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H
Himanshu Singh

Contributor-Level 10

The total seat intake for the BPharm programme at MVN University is 100 seats. These seats are available through the School of Pharmaceutical Science and are allotted based on performance in the entrance exam and subsequent HSTES counselling.

New Question

11 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

11.36 

During the reaction, an alkoxide ion is formed which is then added to an alkyl halide to form the ether via SN2 mechanism.

In the primary step, the nucleophile is formed (O- ) which will the approach to the alkyl halide and after the transition stage, the substitution takes place.

During the reaction, an alkoxide ion is formed which is then added to an alkyl halide to form the ether via SN2 mechanism.

During the reaction, an alkoxide ion is formed which is then added to an alkyl halide to form the ether via SN2 mechanism.

During the reaction, an alkoxide ion is formed which is then added to an alkyl halide to form the ether via

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11 months ago

0 Follower 7 Views

New Question

11 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

11.35 

1-Ethoxy-2-methylpropane

2-Chloro-1-methoxyethane

4-Nitroanisole

1-Methoxypropane

1-Ethoxy-4,4-dimethylcyclohexane

Ethoxy benzene.

New Question

11 months ago

0 Follower 2 Views

New Question

11 months ago

0 Follower

H
Himanshu Singh

Contributor-Level 10

MVN University BPharm cutoff is the minimum rank required for admission via HSTES counselling. It reflects competition levels and is influenced by factors like exam scores, number of applicants, and seat intake. Past closing ranks have ranged around 1276 to 2700, and meeting the cutoff is key to advancing in the admission process.

New Question

11 months ago

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V
Vishal Baghel

Contributor-Level 10

The resonance structures have

(i) The same positions of nuclei, and

(ii) The same number ofunpaired electrons.

New Question

11 months ago

0 Follower 2 Views

S
saurya snehal

Contributor-Level 10

Candidates who have cleared the admission process for the BBA course at BVIMR must pay the course fee in order to secure their admission to the course. The course fee is a combination of various components such as the hostel fee, tuition fee, and the security deposit. 
The fee for BBA at BVIMR is INR 4.56 lakh. 

New Question

11 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

The resonance effect is defined as 'the polarity produced in the molecule by the interaction of two π -bonds or between a π -bond and lone pair of electrons present on an adjacent atom'. The effect is transmitted through the chain. There are two types of resonance or mesomeric effect designated as +R and-R effect.

The atoms or substituent groups, whichrepresent +R or –R electron displacementeffects are as follows:

+R effect: – halogen, –OH, –OR, –OCOR, –NH2, –NHR, –NR2, –NHCOR,

– R effect: – COOH, –CHO, >C=O, – CN, –NO2

New Question

11 months ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

The presence of alternate single and double bonds in an open chain or cyclic system is termed as a conjugated system. These systems often show abnormal behaviour. The examples are 1, 3- butadiene, aniline and nitrobenzene etc. In such systems, the π -electrons are delocalised and the system develops polarity.

New Question

11 months ago

0 Follower 14 Views

J
Jasleen Harsha

Contributor-Level 8

Normalisation of marks are done to adjust difficulty level of question papers.Normalisation formula is Xn= (S2/S1) (X-Xav) + Yav, Xn= Normalized Score of a Candidate. S2= Standard Deviation of raw marks of Base Session. S1= Standard Deviation of raw marks.

New Question

11 months ago

0 Follower 6 Views

V
Vishal Baghel

Contributor-Level 10

Hyperconjugation is a general stabilising interaction. It involves delocalisation of σ electrons of C—H bond of an alkyl group directly attached to an atom of unsaturated system or to an atom with an unshared p orbital. The σ electrons of C—H bond of the alkyl group enter into partial conjugation with the attached unsaturated system or with the unshared p orbital. Greater the hyperconjugation, greater will be the stability of alkenes.

No, hyperconjugation is not a temporary effect. It is a permanent effect.

New Question

11 months ago

0 Follower 17 Views

V
Vishal Baghel

Contributor-Level 10

Steam distillation is applied to separate substances which are steam volatile and are immiscible with water. In steam distillation, steam from a steam generator is passed through a heated flask containing the liquid to be distilled. The mixture of steam and the volatile organic compound is condensed and collected. The compound is later separated from water using a separating funnel. In steam distillation, the liquid boils when the sum of vapour pressures due to the organic liquid (p1) and that due to water (p2) becomes equal to the atmospheric pressure (p), i.e. p =p1+ p2.  Since p1 is lower than p, the organic liquid vaporises at

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New Question

11 months ago

0 Follower 41 Views

A
alok kumar singh

Contributor-Level 10

11.34

Due to the presence of -OH group, ethanol undergoes intermolecular hydrogen bonding which results in the association of molecules.

Therefore, extra energy is required to break those hydrogen bonds. Whereas methoxymethane does not undergo those hydrogen bonding which implies ethanol has a higher boiling point than that of methoxymethane.

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