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Those interested in mental health and therapy can go for clinical or counselling psychology which often needs additional certifications and licensing.

Decision can depend on whether one wants to work directly with people, conduct research or just be in academics.

(b) Iron (III) hexacyanidoferrate (II) (or ferriferrocyanide) Fe₄ [Fe (CN)₆]₃  is the correct answer.

If you are interested in human behavior, mental health and also enjoy helping others then Clinical Psychology can be a great choice.

Students who are patient, empathetic and also good listeners perform best in this area.

• Students who enjoy psychology, counseling, and research.

• Those who are emotionally strong and compassionate.

• Students work hard during long internships and clinical hours.

• Candidates who have an interest in mental health care and therapy.

College ranking is quite important for a Clinical Psychology course. Top-ranked institutes usually have better faculty, clinical exposure, research facilities, and internship tie-ups.

A good college can shape your practical skills and professional network, both crucial in this field. However, personal interest, hands-on experience, and mentorship matter equally. Candidates should balance between college reputation and the quality of training offered.

Mass of the compound = 0.468 g
Mass of barium sulphate= 0.668 g

% of sulphur = 

                     

The syllabus of Clinical Psychology course is mostly medium to hard. You need to really understand how people think, mental health problems, therapy ways, and counselling practice.

Skills that students should have is that they need to be good at thinking, caring about people, and doing research. Some topics like psychopathology and advanced therapy can feel really hard. But if you study regular and do practice, it become easier little by little.

Mass of the compound = 0.3780 g
Mass of silver chloride = 0.5740 g

% of chlorine =

Step I: Calculation of volume of unused acid i.e. V2 =?

V1 = Volume of NAOH solution required = 60 cm³ 

N1 = Normality of NaOH solution = ½ N

N2 = Normality of H₂SO₄ = 1N

Applying N1V1 = N2V2

½ N x 60 cm³ = 1N x V2

Or V2 = 30 cm³

Step II: calculation of volume of acid used

Volume of acid added = 50 cm³

Volume of unused acid = 30 cm³

Volume of acid used = 50 – 30 = 20 cm³

Step III: Calculation of % of nitrogen

Mass of compound = 0.50 g

Volume of acid used = 20 cm³

Normality of acid used = 1 N

% of nitrogen = (1.4 x 20 x 1) / 0.50 = 56%

Step 1: Calculation of mass of CO₂ produced

Mass of compound = 0.20 g

% of carbon = 69%

i.e. 12/44 x  = Mass of Carbondioxide formed / Mass of Compound = 69/100

Therefore, mass of CO₂formed = (69 x 44 x 0.20) / (12 x 100) = 0.506 g

Step 2: Calculation of mass of H₂O produced

Mass of compound = 0.20 g

% of hydrogen = 4.8%

i.e. 2/18 x Mass of Water Formed/Mass of Compound = 4.8/100

Therefore, mass of H₂O formed = 4.8*18*0.20/2*100 = 0.0864 g

11.24

The reaction given below is:

Benzene reacts with concern. H₂SO₄ and undergoes the following mechanism:-

Step 1: The equilibrium produces SO₃ in concentrated H₂SO₄, as shown below:

Step 2: SO₃ is the electrophile which reacts with benzene to form arenium ion, as shown below:

Step 3: A proton is removed from the arenium ion to form benzenesulfonate ion.

Step 4: The benzenesulfonate ion accepts a proton to become benzene-sulphonic acid, as shown below:

Step 5: The benzene sulphonic acid then reacts with NaOH to give phenol as the final product, as shown below:

It necessary to use acetic acid and not sulphuric acid for acidification of sodium extract for testing sulphur by lead acetate test because sulphuric acid will react with lead acetate to form a white precipitate of lead sulphate which will interfere in the test of sulphur.

Pb (OCOCH₃)₂ + H₂SO₄ →PbSO₄  + 2CH₃COOH

CO₂ is acidic in nature and therefore, it reacts with the strong base KOH to form K₂CO₃.

2KOH + CO₂ ? K₂CO₃+ H₂O.

No. CCl₄ is a completely non-polar covalent compound whereas AgNO₃ is ionic in nature. Therefore, they are not expected to react and thus a white precipitate of silver chloride will not be formed.

It is because in steam distillation the sum of vapour pressure of organic compound and steam should be equal to atmospheric pressure.

Sublimation can be used for the separation of the two compounds because camphor can sublime whereas CaSO₄ does not.

Organic compound is fused with sodium metal so as to convert organic compounds into NaCN,  Na₂S, NaX and Na₃PO₄. Since these are ionic compounds and become more reactive and thus can be easily tested by suitable reagents.

Nitric acid is added to sodium extract so as to decompose NaCN to HCN and Na₂S to H₂S and to expel these gases.

NaCN + HNO₃ ——-> NaNO₃ + HCN
Na₂S + 2HNO₃ ——> 2NaNO₃ + H₂S